We have 60 gallons of 20% antifreeze.
How much 70% antifreeze do we add to get 60% antifreeze?
We'll make "x" the gallons of 70% we must add.
.20 * 60 + .70 x = .60 * (60 + x)
12 + .70x = 36 + .60x
.10x = 24
x = 240 gallons of 70% antifreeze.
Source
1728.com/mixture.htm (see example B)
The first one is 6 1/6 feet
2/5=6/15
1/3=5/15
11/15
yes. that would be the last one possible.
You could give all of the fractions a common denominator. You could also solve each of them (1/2=0.5) to see their value and order them through the value.
