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velikii [3]
3 years ago
5

at current prices, roberta can drive her car 8.2 miles per dollar of gasoline that she buys. Roberta and three of her friends de

cide to go on a road trip to a neighboring university that is 105 miles away and agree to split the cost evenly . to the nearest cent, how much money will each have to contribute to get to the university and back?
Mathematics
1 answer:
Gekata [30.6K]3 years ago
7 0

Answer:

I think it's $12.80 but I might be wrong.

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X² - 6
Ipatiy [6.2K]

Answer:

x² - 6

Evaluate g(n - 7) if g(x)

7x

a.

22 - 1472 + 43

c.

72

- 1472 + 43

72 - 49

77 - 7

b.

222 - 6

d.

72 - 7

7

772

T2 – 343

Please select the best answer from the choices provided

Ο Α

B

С

D

7 0
3 years ago
HCF of 522, 1624, 1276​
hichkok12 [17]

Answer and Step-by-step explanation:

We~ need ~to ~find ~the~ HCF~ of ~1624, 522 ~and~ 1276~so~in~order~to~find~this we~will~have~to~use~prime~factorization.

<u><em>→ Prime factorization of 1624  is :</em></u>

= 2 × 2 × 2 × 7 × 29

<u><em>→ Prime factorisation of 522  is :</em></u><em> </em>

= 2 × 3 × 3 × 29

<u><em>→ Prime factorisation of 1276  is :</em></u><em> </em>

= 2 × 2 × 29 × 11

→ HCF~of~1624 , 522 , 1276~is:<em>  </em>=2× 29=58

8 0
4 years ago
Read 2 more answers
Use the empirical rule to solve the problem. The annual precipitation for one city is normally distributed with a mean of 288 in
nadezda [96]

Answer:

z=-1.99

z=1.99

And if we solve for a we got

a=288 -1.99*3.7=214.4

a=288 +1.99*3.7=295.4

And the limits for this case are: (214.4; 295.4)

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the annual precipitation of a population, and for this case we know the distribution for X is given by:

X \sim N(288,3.7)  

Where \mu=288 and \sigma=3.7

The confidence level is 95.44 and the signficance is 1-0.9544=0.0456 and the value of \alpha/2 =0.0228. And the critical value for this case is z = \pm 1.99

Using this condition we can find the limits

z=-1.99

z=1.99

And if we solve for a we got

a=288 -1.99*3.7=214.4

a=288 +1.99*3.7=295.4

And the limits for this case are: (214.4; 295.4)

8 0
3 years ago
Hello could i please get some quick help can someone help solve 2x+3=10
ki77a [65]

Answer:

x= 3.5

Step-by-step explanation:

2x + 3 = 10       (-3)

2x = 7       (divide by 2 )

x = 3.5

8 0
3 years ago
Eleven less than three times a number
Ber [7]
The answer to this question could be 44
8 0
3 years ago
Read 2 more answers
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