Answer:
3 times
Explanation:
When the dough is folded, it increases by a constant factor. We can model the growth of the thickness using the exponential growth model
Where:
Initial thickness, 
= 2mm
Growth factor, r =8%=0.08
We want to find the smallest number of times Soon Yi will have to roll and fold the dough so that the resulting dough is at least 2.5mm.
i.e When 
Therefore, the smallest number of times Soon Yi will have to roll and fold the dough so that the resulting dough is at least 2.5mm thick is 3.
I was playing my game mom said go feed the dogs i said no the i thought about it and i need to feed them
Answer:
0.67038
Explanation:
One z-value is negative and the other is positive.
This means we are looking for area between the two given z-values on opposite sides of the mean.
From z-table attached, the area at z = -2.31 is 0.98956
Also, from the second z-table attached, the area at z = 0.47 is 0.68082
But since we are looking for the area between both z-scores, we will now have;
P(-2.31 < x < 0.47) = (0.98956 + 0.68082) - 1
P(-2.31 < x < 0.47) = 0.67038
