The object reaches the lowest height at 5 seconds
<h3>How to determine the time?</h3>
The function is given as:
f(t) = -2t² +22t + 6
Differentiate the function
f'(t) = -4t +22
Set to 0
-4t +22 = 0
Subtract 22 from both sides
-4t = -22
Divide both sides by -4
t = 5.5
Remove decimal points
t = 5
Hence, the object reaches the lowest height at 5 seconds
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A)


b)
since QR=QP, that means that QO is an angle bisector, and thus the segments it makes at the bottom of RO and OP, are also equal, thus RO=OP
thus, since the point P is 0.5 units away from the 0, point R is also 0.5 units away from 0 as well, however, is on the negative side, thus R (-0.5, 0)
c)
what's the equation of a line that passes through the points (-0.5, 0) and (0,2)?

Answer:
n = 30m + 1,200
Step-by-step explanation:
let n = gallons
m = minutes
There are 30 gallons per minute, so 30 is multiplied by the minutes, and because there are already 1,200 gallons of water, you add 1,200
Answer:
Step-by-step explanation:
mean is average, so if we label the first through fifth days of january a-e we can solve it.
So average of the first four is (a+b+c+d)/4 = 1 and the first five is (a+b+c+d+e)/5 = 2. Since it's easy, let's get rid of the fraction in both.
(a+b+c+d)/4 = 1 and (a+b+c+d+e)/5 = 2
a+b+c+d = 4 and a+b+c+d+e = 10
Now, we know a+b+c+d is 4, so we can replace that in the second equation
a+b+c+d+e = 10
4 + e = 10
e = 6
ad since e is the fifth day, we know the temperature of it. Let me know if something here didn't make sense.