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3 years ago

40 POINTS PLEASE HELP ASAP!!

Mathematics

2 answers:

eduard3 years ago

7 0

The answer world be D 8 pounds

ira [324]3 years ago

5 0

D) 8 pounds

6/3 pounds is the same as 2 pounds, since 6÷3 is 2

From there, it's simply multiplying 2×4

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The height in feet is modelled by the function below, where the t is in

Sedaia [141]

The object reaches the lowest height at 5 seconds

<h3>How to determine the time?</h3>

The function is given as:

f(t) = -2t² +22t + 6

Differentiate the function

f'(t) = -4t +22

Set to 0

-4t +22 = 0

Subtract 22 from both sides

-4t = -22

Divide both sides by -4

t = 5.5

Remove decimal points

t = 5

Hence, the object reaches the lowest height at 5 seconds

Read more about quadratic functions at:

brainly.com/question/1214333

#SPJ1

6 0

2 years ago

Write at least three expressions that are equivalent to 3(2x - 5)

myrzilka [38]

Answer:

6x - 15

6x - (5 · 3)

(3 · 2x) - 15

6 0

3 years ago

Read 2 more answers

Help me with question a please ! With full workings !

frosja888 [35]

A)

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
% (c,d)
P&({{ 0.5}}\quad ,&{{ 0}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}$

$\bf QP=\sqrt{(0.5-0)^2+(0-2)^2}\implies QP=\sqrt{0.5^2+2^2}
\\\\\\
QP=\sqrt{\left( \frac{1}{2} \right)^2+4}\implies QP=\sqrt{ \frac{1^2}{2^2}+4}\implies QP=\sqrt{\frac{1}{4}+4}
\\\\\\
QP=\sqrt{\frac{17}{4}}\implies QP=\cfrac{\sqrt{17}}{\sqrt{4}}\implies QP=\cfrac{\sqrt{17}}{2}$

b)

since QR=QP, that means that QO is an angle bisector, and thus the segments it makes at the bottom of RO and OP, are also equal, thus RO=OP

thus, since the point P is 0.5 units away from the 0, point R is also 0.5 units away from 0 as well, however, is on the negative side, thus R (-0.5, 0)

c)

what's the equation of a line that passes through the points (-0.5, 0) and (0,2)?

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
% (c,d)
R&({{ -0.5}}\quad ,&{{ 0}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{0-2}{-0.5-0}\implies \cfrac{-2}{-0.5}$

$\bf m=\cfrac{\frac{-2}{1}}{-\frac{1}{2}}\implies \cfrac{-2}{1}\cdot \cfrac{2}{-1}\implies 4
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-2=4(x-0)\implies y=4x+2\\
\left. \qquad \right. \uparrow\\
\textit{point-slope form}$

7 0

3 years ago

There are already 1,200 gallons of water in a swimming pool. If water is filling the pool at a rate of 30 gallons per minute, wh

Alika [10]

Answer:

n = 30m + 1,200

Step-by-step explanation:

let n = gallons

m = minutes

There are 30 gallons per minute, so 30 is multiplied by the minutes, and because there are already 1,200 gallons of water, you add 1,200

4 0

3 years ago

The mean temperature for the first 4 days in january was 1°C. The mean temperature of the first 5 days in January was 2°C. What

Lorico [155]

Answer:

Step-by-step explanation:

mean is average, so if we label the first through fifth days of january a-e we can solve it.

So average of the first four is (a+b+c+d)/4 = 1 and the first five is (a+b+c+d+e)/5 = 2. Since it's easy, let's get rid of the fraction in both.

(a+b+c+d)/4 = 1 and (a+b+c+d+e)/5 = 2

a+b+c+d = 4 and a+b+c+d+e = 10

Now, we know a+b+c+d is 4, so we can replace that in the second equation

a+b+c+d+e = 10

4 + e = 10

e = 6

ad since e is the fifth day, we know the temperature of it. Let me know if something here didn't make sense.

4 0

2 years ago

Read 2 more answers