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3 years ago

What is a volumetric flask

Physics

1 answer:

Karo-lina-s [1.5K]3 years ago

3 0

A volumetric flask is a piece of laboratory glassware used to prepare and measure chemical solutions.

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A 100 Ω resistive heater in a tank of water (1kg) increases its temperature from 10°C to 20°C over a period of 1 hour. During th

Nookie1986 [14]

Answer:48.52 kJ

Explanation:

Given

Resistance $=100 \Omega$

temperature increases from $10^{\circ}C to 20^{\circ}C$

Voltage=50 V

Heat given(H) $=\frac{V^2t}{R}$

Where V=voltage applied

t=time

R=Resistance

$H=\frac{50^2\times 60\times 60}{100}=90 kJ$

Heat absorbed by water is

$Q=mc(\Delta T)$

where

m=mass of water

c=specific heat of water

$\Delta T$ =change in temperature

$Q=1000\times 4.184\times (20-10)=41.48 kJ$

Therefore 90-41.48=48.52 kJ is not absorbed by water and leaves the system into the surroundings.

8 0

3 years ago

Hello guys I have a quick question and please help me! Thanks!

xenn [34]

Answer: 4 herz is the answer!

Explanation:

6 0

3 years ago

Read 2 more answers

Explain why fishes survive in ponds even when the temperature is below 0°c

zmey [24]

Answer:

After sufficient thickness of ice is formed it prevents further loss of heat from the bottom layers of water. This is why fishes and other aquatic animals and plants can survive in ponds and other water bodies even when the atmospheric temperature reaches or is well below 0 degrees.The anomalous expansion of water helps preserve aquatic life during very cold weather. When temperature falls, the top layer of water in a pond contracts becomes denser and sinks to the bottom. ... Thus, even though the upper layer are frozen, the water near the bottom is at 4°C and the fishes can survive in it easily.

3 0

3 years ago

A tuba may be treated like a tube closed at one end. If a tuba has a fundamental frequency of 88.4 Hz, determine the first three

yulyashka [42]

Answer with Explanation:

We are given that

Fundamental frequency,f=88.4 Hz

Speed of sound,v=343 m/s

We have to find the first three overtones.

Tube is closed

The overtone of closed pipe is equal to odd number of fundamental frequency.

Therefore, the overtone of tuba

$f'=nf$

Where n=3,5,7,..

Substitute n=3

$f'=3\times 88.4=265.2Hz$

For second overtone

$f'=5\times 88.4=442Hz$

For third overtone

$f'=7\times 88.4=618.8Hz$

4 0

4 years ago

An aluminum cylinder with a radius of 2.7 cm and a height of 67 cm is used as one leg of a workbench. The workbench pushes down

soldier1979 [14.2K]

Answer:

$1.9\times 10^{-4}$

$1.2\times 10^{-4}\ m$

Explanation:

r = Radius = 2.7 cm

F = Force = $3.2\times 10^4\ N$

A = Area = $\pi r^2$

$\sigma$ = Stress = $\frac{F}{A}$

E = Young's modulus = $7\times 10^{10}\ Pa$

$\epsilon$ = Strain

$L_0$ = Original length = 67 cm

$\Delta L$ = Change in length

Young's modulus is given by

$E=\frac{\sigma}{\epsilon}\\\Rightarrow \epsilon=\frac{\sigma}{E}\\\Rightarrow \epsilon=\frac{\frac{3.2\times 10^4}{\pi 0.027^2}}{7\times 10^{10}}\\\Rightarrow \epsilon=0.0001996=1.9\times 10^{-4}$

Strain is $1.9\times 10^{-4}$

Strain is given by

$\epsilon=\frac{\Delta L}{L_0}\\\Rightarrow \Delta L=\epsilon\times L_0\\\Rightarrow \Delta L=1.9\times 10^{-4}\times 0.67\\\Rightarrow \Delta L=0.0001273\\\Rightarrow \Delta L=1.2\times 10^{-4}\ m$

The cylinder height decreases by $1.2\times 10^{-4}\ m$

3 0

3 years ago