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Harman [31]
3 years ago
11

Sulfur hexafluoride is represented by which formula? A) sf2 b) sf7 c) s2f5 d) sf6

Physics
2 answers:
Margarita [4]3 years ago
4 0
Since hex means 6 from Greek, the answer is D) SF6
belka [17]3 years ago
3 0

The answer is d) sf6

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A car is traveling 35 mph on a smooth surface. If a balanced force is applied to the car, what happens?
zepelin [54]

Answer:

Here is the answer.

Explanation:

Balanced forces- they are those forces that produce 0 resultant forces.

therefore, on applying a balanced force on the object, it wouldn't result in any change, as resultant force would be 0.

7 0
3 years ago
If you help me with the correct answer I will give you the brainlist
gulaghasi [49]

Answer:

1. A force is a push or pull upon an object resulting from the object's interaction with another object.  

Explanation:

6 0
2 years ago
If the pendulum is brought on the moon where the gravitational acceleration is about g/6, approximately what will its period now
Andru [333]

Answer:

The new period will be √6 *T

Explanation:

period ,T=2π√(L/g)       ................equation 1

where T is the period on earth

gravitational acceleration on the moon is g/6

T1 = 2π√[L/(g/6)]

T1=2π√(6L/g)               ...............equation 2

divide equation 2 by 1

T1/T =2π√(6L/g)÷2π√(L/g)

T1/T =√(6L/L)

T1/T =√6

T1 = √6 *T

5 0
3 years ago
Is it possible for one energy store to transfer into another energy store ?Explained answer
liraira [26]

Answer:

Yes

Explanation:

Energy can be transferred from one object to another or between energy stores within the same object. For example on a pool table when white ball hits another ball energy is transferred from the kinetic store of the white ball to the kinetic store of the other ball.

6 0
3 years ago
Read 2 more answers
A load of 800 N is lifted using a block and tackle having 5 pulleys. If the applied effort is 200 N, calculate
ser-zykov [4K]

Explanation:

Load=800N

Effort=200N

1. Mechanical Advantage = LOAD/EFFORT

= 800N/200N

= 4

2 Velocity Ratio = no. Of pulleys =5

3. Efficiency = Mechanical advantage / velocity ratio × 100%

= (4/5)×100%

=80%

4. output work= load×load distance

= 800N × 5m

= 4 × 1000J

5. Efficiency = (output work/input work) ×100%

Or, 80% = (4000J/input work) ×100%

Or, 80%/100% = 4000J/inputwork

Or, 4/5 = 4000J/inputwork

Or, input work =4000J × 5/4

Input work = 5×1000J

I hope it helped! ;-)

8 0
3 years ago
Read 2 more answers
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