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galben [10]
3 years ago
6

Madam Siti bought the same lengths of red and yellow ribbons. After she used 836 cm of the red ribbon, the length of the yellow

ribbon was 5 times the length of the remaining red ribbon. What was the original total length of the two ribbons?
Mathematics
2 answers:
Leya [2.2K]3 years ago
7 0

Answer:

Step-by-step explanation:

Yuliya22 [10]3 years ago
5 0

Answer: 1045 cm of red ribbon and 1045 cm of yellow ribbon

<u>Step-by-step explanation:</u>

Let R represent the amount red ribbon and Y represent the amouont of yellow ribbon.

  • bought the same lengths of red and yellow: R = Y
  • after used 286 of red, yellow is 5 times the remaining red; 5(R - 836) = Y

Use substitution method to solve:

5(R - 836) = R

5R - 4180 = R   <em>distributed 5 on the left side</em>

4R - 4180 = 0   <em>subtracted R from both sides</em>

4R = 4180         <em>added 4180 to both sides</em>

R = 1045         <em>divided both sides by 4</em>


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In the figure, triangle CAE is an enlargement of triangle CBD with scale factor of 4/3. The area of the smaller triangle is 9cm2
balandron [24]

Answer:

16 cm^2

Step-by-step explanation:

Given

\triangle CAE -- Bigger Triangle

\triangle CBD -- Smaller Triangle

k = \frac{4}{3} --- Scale factor

Area of CBD = 9

Required

Determine the area of CAE

The area of triangle CBD is:

A_1 = \frac{1}{2}bh

\frac{1}{2}bh = 9

The area of CAE is:

A_2 = \frac{1}{2}BH

Where:

B = \frac{4}{3}b and

H = \frac{4}{3}h

The above values is the dimension of the larger triangle (after dilation).

So, we have:

A_2 = \frac{1}{2}*\frac{4}{3}b * \frac{4}{3} * h

A_2 = \frac{1}{2}*\frac{4}{3} * \frac{4}{3} *b* h

A_2 = \frac{1}{2}*\frac{16}{9}  *b* h

Re-order

A_2 = \frac{16}{9}*\frac{1}{2}* b* h

A_2 = \frac{16}{9}*\frac{1}{2}bh

Recall that:

\frac{1}{2}bh = 9

A_2 = \frac{16}{9}*9

A_2 = 16

Hence, the area is 16 cm^2

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3 years ago
What is the measure of angle A???
Dmitriy789 [7]

Answer:

41.5

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