The least common multiple is 2. 2 is the highest number that goes in to each of these numbers.
It is between the first two I believe it is the first one I am not absolutly sure though
Answer:

Step-by-step explanation:
We know that:
In a deck of 52 cards there are 4 aces.
Therefore the probability of obtaining an ace is:
P (x) = 4/52
The probability of not getting an ace is:
P ('x) = 1-4 / 52
P ('x) = 48/52
In this problem the number of aces obtained when extracting cards from the deck is a discrete random variable.
For a discrete random variable V, the expected value is defined as:

Where V is the value that the random variable can take and P (V) is the probability that it takes that value.
We have the following equation for the expected value:

In this problem the variable V can take the value V = 9 if an ace of the deck is obtained, with probability of 4/52, and can take the value V = -1 if an ace of the deck is not obtained, with a probability of 48 / 52
Therefore, expected value for V, the number of points obtained in the game is:

So:

At the start, you have 10 marbles in total and 6 red marbles. The probability of the first event is 6/10.
Since you do not place the marble back in, you now have 9 marbles in total and 3 blue marbles. This probability of the second event is 3/9.
To find the probability of both events occurring, we multiply the two probabilities together. (6•3)/(10•9)=18/90=1/5
Thus, there is a 20% chance of drawing a red marble then a blue marble without placing the red marble back in the bag.
Answer:
7 for $32.76
Step-by-step explanation:
23.60/5 is $4.72
32.76/7 is $4.68