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3 years ago

Find the distance labeled x in the diagram.

Mathematics

1 answer:

zheka24 [161]3 years ago

6 0

Answer: B

Step-by-step explanation:????

Troll

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Enita is factoring the expression 32 a b minus 8 b. She determines the GCF and writes the factored expression as 8 b (4 a minus

sattari [20]

This shows that the greatest common factor is 8, Hence Venita's error is that she incorrectly determined the GCF.

<h3>Greatest common factor</h3>

Given the following expression

32ab - 8

Find the factors of each terms

32ab = 8 * 4. * a * b

8 = 8 * 1

Since 8 is common to both factors, hence

32ab - 8 = 8(4ab -1)

This shows that the greatest common factor is 8, Hence Venita's error is that she incorrectly determined the GCF.

Learn more on GCF here; brainly.com/question/219464

#SPJ1

8 0

2 years ago

Solve the inequality. 12x – 3x + 11 > 4x – (17 – 9x)

musickatia [10]

Answer:

20>4

Step-by-step explanation:

12-3 forget about the x 12-3=9 . 9+11=20

(17-9)=8 . 8-4 =4

so your answer is correct

6 0

4 years ago

Read 2 more answers

If a sponsored link was delivered 100 times and 10 people clicked on it, then the number of impressions is 100, the number of cl

Rudik [331]

Answer:

Option A.

Step-by-step explanation:

It is given that a sponsored link was delivered 100 times and 10 people clicked on it.

Number of impressions = 100

Number of clicks = 10

The formula for click-through-rate (CTR) is

$CTC=\dfrac{\text{Total measured clicks}}{\text{Total measured impression}}\times 100$

$CTC=\dfrac{10}{100}\times 100$

$CTC=10$

The click-through-rate (CTR) would be 10%. Therefore, the correct option is A.

7 0

3 years ago

A new security system needs to be evaluated in the airport. The probability of a person being a security hazard is 4%. At the ch

ivolga24 [154]

Answer:

(a) 0.9412

(b) 0.9996 ≈ 1

Step-by-step explanation:

Denote the events a follows:

$P$ = a person passes the security system

$H$ = a person is a security hazard

Given:

$P (H) = 0.04,\ P(P^{c}|H^{c})=0.02\ and\ P(P|H)=0.01$

Then,

$P(H^{c})=1-P(H)=1-0.04=0.96\\P(P|H^{c})=1-P(P|H)=1-0.02=0.98\\$

(a)

Compute the probability that a person passes the security system using the total probability rule as follows:

The total probability rule states that: $P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})$

The value of P (P) is:

$P(P)=P(P|H)P(H)+P(P|H^{c})P(H^{c})\\=(0.01\times0.04)+(0.98\times0.96)\\=0.9412$

Thus, the probability that a person passes the security system is 0.9412.

(b)

Compute the probability that a person who passes through the system is without any security problems as follows:

$P(H^{c}|P)=\frac{P(P|H^{c})P(H^{c})}{P(P)} \\=\frac{0.98\times0.96}{0.9412} \\=0.9996\\\approx1$

Thus, the probability that a person who passes through the system is without any security problems is approximately 1.

7 0

3 years ago

What is the multiplicative inverse of -1/3

motikmotik

-1/3 . -3/1 = 1
......................

4 0

4 years ago