You can not work out it unless provided initial distance between the house and shoreline.
You either give the nonmembers a £2 fee for aerobic classes or minus the members fee by £1
In this case, we cannot simply take the average speed by
adding the two speeds and divide by two.
What we have to do is to calculate the time required
going to school and the return trip home.
We know that to calculate time, we use the formula:
t = d / v
where,
d = distance = 4.8 km = 4800 m
v = velocity
Let us say that the variables related to the trip going
to school is associated with 1, and the return trip home is 2. So,
t1 = 4800 m / (22.6 m / s)
t1 = 212.39 s
t2 = 4800 / (16.8 m / s)
t2 = 285.71 s
total time, t = t1 + t2
t = 498.1 s
Therefore the total average velocity is:
= (4800 m + 4800 m) / 498.1 s
= 19.27 m / s = 19.3 m / s
Answer:
19.3 m/s
H=-t^2+95
The y intercept here is 95, and it represented from where the boy threw the ball.
If he threw it from 95 ft above the ground, the best answer for where he is is on a bridge.
His backyard is at 0 ft (sea level). An underground cave is below sea level. A ladder is probably not 95 ft.
Final answer: D
Answer:
4/45
Step-by-step explanation:
Multiply the top by the top, and the bottom by the bottom:
4/45 cannot be reduced down anymore, therefore that is your answer.
<em>Hope this helps!!</em>
<em>- Kay :)</em>
