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V125BC [204]
3 years ago
13

2/5y+y-4=31 solve for x

Mathematics
2 answers:
astraxan [27]3 years ago
5 0
12tttttttttttttttttttttttt
djverab [1.8K]3 years ago
3 0
Y=25

Have an amazing day!
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A popular soft drink is sold in 2-liter (2000 milliliter) bottles. Because of variation in the filling process, bottles have a m
andrezito [222]

Answer:

a) 0.27% probability that the mean is less than 1995 milliliters.

b) 2002.3 milliliters or more will occur only 10% of the time for the sample of 100 bottles.

Step-by-step explanation:

To solve this problem, it is important to understand the normal probability distribution and the central limit theorem

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 2000, \sigma = 18

A) If the manufacturer samples 100 bottles, what is the probability that the mean is less than 1995 milliliters?

So n = 100, s = \frac{18}{\sqrt{100}} = 1.8

This probability is the pvalue of Z when X = 1995. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{1995 - 2000}{1.8}

Z = -2.78

Z = -2.78 has a pvalue of 0.0027

So 0.27% probability that the mean is less than 1995 milliliters.

B) What mean overfill or more will occur only 10% of the time for the sample of 100 bottles?

This is the value of X when Z has a pvalue of 1-0.1 = 0.9.

So it is X when Z = 1.28

Z = \frac{X - \mu}{s}

1.28 = \frac{X - 2000}{1.8}

X - 2000 = 1.8*1.28

X = 2002.3

2002.3 milliliters or more will occur only 10% of the time for the sample of 100 bottles.

3 0
3 years ago
Need the answer asap
LiRa [457]

Answer:

cant see the entire picture sry

Step-by-step explanation:

7 0
3 years ago
Scores from an exam are normally distributed with a mean of 85 and a standard deviation of 5. Suppose 188 students take the exam
charle [14.2K]

The mean is \mu=85 and standard deviation is \sigma=5. Then the variable X\sim N(85,5).

Use substitution Z=\dfrac{X-\mu}{\sigma}=\dfrac{X-85}{5}, then the variable Z\sim N(0,1).

The probability Pr(X>80) can be calculated in the following way:

for X=80, Z=\dfrac{80-85}{5} =-1 and Pr(X>80)=Pr(Z>-1). From the diagram Pr(Z>-1)=0.34+0.34+0.135+0.025=0.84.

Conclusion: if 188 students take the exam, then 188·0.84=157.92 (157) would receive a score above 80

4 0
3 years ago
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Hmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm<br>​
allsm [11]

Answer:

C is the correct answer

8 0
3 years ago
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Please just help me im literally crying I dont want links to your math websites our teacher didnt teach us like half this stuff
8090 [49]

Answer:

Okay?

Step-by-step explanation:

I think m a week or 2 late

8 0
2 years ago
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