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Arlecino [84]
3 years ago
12

I need help!!!!! Help Needed!!!!!!!!!!!

Mathematics
1 answer:
dangina [55]3 years ago
8 0
Is there any more information than just that picture? Please tell me
You might be interested in
Let a=3/4 and b=1/5. If a*x=b, then what is x?
Anarel [89]

In general, any equation like ax=b (assuming a \neq 0) is solved by

x= \dfrac{b}{a}

So, in your case, the solution is

x = \dfrac{\frac{1}{5}}{\frac{3}{4}}

Dividing by a fraction means to multiply by the inverse of that fraction:

\dfrac{\frac{1}{5}}{\frac{3}{4}} = \dfrac{1}{5} \cdot \dfrac{4}{3} = \dfrac{4}{15}

7 0
3 years ago
I need help and can u explain how to do it please and thank u
lorasvet [3.4K]

Answer:

[See Below]

Step-by-step explanation:

✦ Formula: πr^{2}

  • π6^{2}=113.0973355

✦ Round:

  • 113.0973355=113.1

So your answer would be C, 113.1 ~cm^{2}.

~<em>Hope this helps Mate. If you need anything feel free to message me. </em>

7 0
3 years ago
Tossing a coin and spinning a spinner with five equal sections, 1-5
LUCKY_DIMON [66]

Answer:

Its gonna be a 50/50 on the coin and 20/100 chance for the spinner

5 0
3 years ago
Read 2 more answers
Five standard six-sided dice are rolled. We are told there is no three-of-a-kind, but there is a pair of dice that show the same
Neko [114]

The probability that after re-rolling these three dice, at least three of the five dice show the same value is  \frac{4}{9}

Of the three dice rolled, one may match the original pair and two are different, and this can occur three ways:

(\frac16 \times \frac56 \times \frac56 ) + ( \frac56 \times \frac16 \times \frac56 ) + ( \frac56 \times \frac 56 \times \frac 16 )  =  \frac {75}{216}

[ where \frac{1}{6} is the probability of matching the first two and \frac{5}{6} is the probability of not matching the first two ]

Or, two may match the original pair and one is different

( \frac16 \times \frac16 \times \frac 56 ) + ( \frac16 \times \frac56 \times \frac 16 ) + ( \frac56 \times \frac16 \times \frac16 )  = \frac {15}{216}

Or, all three may match the original pair

( \frac 16 \times \frac 16 \times \frac 16 )  = \frac {1}{216}

Or, all three may  be the same, but not match the original pair:

( \frac 56 \times \frac 16 \times\frac 16 )  =  \frac {5}{216}

[ where \frac{5}{6} is the probability of getting a new number and \frac{1}{6} is the probability of matching that new number ]

Adding these together: \frac {75}{216} + \frac {15}{216} + \frac 1{216} + \frac 5{216}  =  \frac {96}{216}  = \frac 49

To learn more about probability with the given link

brainly.com/question/11234923

#SPJ4

3 0
2 years ago
I need another help again my bros​
andrew11 [14]

Answer:

a = 15.59   c= 31.18

27 tan 30 = a

c cos 30 = 27

c = 27/cos30

c = 31.18

3 0
4 years ago
Read 2 more answers
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