The answer to this item is SOMETIMES. There are quotient of whole numbers that are also whole number such as that of 6 / 3 = 2. However, there exists a ratio between 4 and 3 which gives an answer of 4/3 or 1.33333.
Answer:
x = –4
Step-by-step explanation:
x = –koef x / (2•koef x²)
Answer/Step-by-step explanation:
The angles where two unequal sides of a kite meet are congruent to each other. Thus, these two opposite angles in a kite are equal to each other.
Therefore:
7. <E = <G
Sum of interior angles of a quadrilateral = 360
Thus,
<E = (360 - (150 + 90))/2
<E = 120/2
<E = 60°
<E = <G (set of congruent opposite angles of a kite)
Therefore,
<G = 60°
8. <H = <F (set of congruent opposite angles of a kite)
<F = right angle = 90°
Therefore:
<H = 90°
<G = 360 - (90 + 110 + 90) (sum of quadrilateral)
<G = 70°
9. Based on trapezoid midsegment theorem, the equation should be:
MN = (AB + DC)/2
Thus:
8 = (14 + DC)/2
8 * 2 = 14 + DC
16 = 14 + DC
16 - 14 = DC
2 = DC
DC = 2
10. A kite has only one set of opposite angles that are congruent to each other. The angles where the unequal sides meet, <B and <D, is the only set of angles that are congruent.
Therefore, m<A ≠ 50°
Rather, m<B = m<D = 120°
m<A = 360 - (120 + 120 + 50) (sum of quadrilateral)
m<A = 70°
Answer:
No its not
Step-by-step explanation:
0.373 seconds. First, calculate the initial vertical velocity of the shell. 800sin(30) = 800*0.5 = 400 m/s Now the formula for the distance traveled is d = 400 m/s * T + 0.5A T^2 Substituting known values gives. 150 = 400 m/s * T + 0.5*9.80m/s^2 T^2 150 = 400 m/s * T + 4.9 m/s^2 T^2 Arrange as a quadratic formula 0 = 400 m/s * T + 4.9 m/s^2 T^2 - 150 4.9 m/s^2 T^2 + 400 m/s * T - 150 = 0 Now solve for T using the quadratic formula with a=4.9, b=400, and c=-150 The calculated value is 0.373 seconds. Is this value reasonable? Let's check. The initial downward velocity is 400 m/s. So 150/400 = 0.375 seconds. Since the actual time will be a bit less due to acceleration by gravity and since the total time is so short, there won't be much acceleration due to gravity, the value of 0.373 is quite reasonable.