Determine whether triangle TJD is congruent to triangle SEK given T (-4,-2), J (0,5), D (1,-1), S (-1,3), E (3,10), K (4,4) and
nataly862011 [7]
Yes, it is.
The three points of triangle SEK are the points of TJD shifted 3 units right and 5 units upward.
So they are the same triangle, just translated in the plane.
Answer:
<h2>248 Songs</h2>
Step-by-step explanation:
<h3>
Step 1; Set up an equation</h3>
4l + 6l + l = 682
<h3>Step 2: Add like terms</h3>
11l = 682
<h3>Step 3: Divide by 11</h3>
l = 62
Lou has 62 songs
<h3>Step 4: Multiply by 4</h3>
Kelly has 248 songs
<h3>Step 5: Check</h3>
Kelly has 248 songs
Lou has 62 songs
Tiffany has 372 songs
Is 248 4 times 62? ✔
Is 372 6 times 62? ✔
Is 248 + 372 + 62 = 682? ✔
<h3>Step 6: Answers</h3>
Kelly has 248 songs
Lou has 62 songs
Tiffany has 372 songs
I'm always happy to help :)
The order from least to greatest is 4 7/ 8, 4 9/ 10 , 5
<h3>What are fractions?</h3>
Fractions are simply representatives of part of a whole.
The types of fraction are;
- Mixed fractions
- Simple fractions
- Improper fractions
- Proper fractions
From the information given, we have to arrange in order from least to greatest
5, 4 7/8, 4 9/10
Turn mixed fractions to improper fractions;
5, 39/ 8 , 49/ 10
From least to greatest is written thus;
39/ 8, 49/ 10 , 5
Thus, the order from least to greatest is 4 7/ 8, 4 9/ 10 , 5
Learn more about fractions here:
brainly.com/question/11562149
#SPJ1
Answer:
![A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-4%262%5C%5C2%266%26-6%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Given
![T:R^3->R^2](https://tex.z-dn.net/?f=T%3AR%5E3-%3ER%5E2)
![T(e_1) = (1,2)](https://tex.z-dn.net/?f=T%28e_1%29%20%3D%20%281%2C2%29)
![T(e_2) = (-4,6)](https://tex.z-dn.net/?f=T%28e_2%29%20%3D%20%28-4%2C6%29)
![T(e_3) = (2,-6)](https://tex.z-dn.net/?f=T%28e_3%29%20%3D%20%282%2C-6%29)
Required
Find the standard matrix
The standard matrix (A) is given by
![Ax = T(x)](https://tex.z-dn.net/?f=Ax%20%3D%20T%28x%29)
Where
![T(x) = [T(e_1)\ T(e_2)\ T(e_3)]\left[\begin{array}{c}x_1&x_2&x_3\\-&&x_n\end{array}\right]](https://tex.z-dn.net/?f=T%28x%29%20%3D%20%5BT%28e_1%29%5C%20T%28e_2%29%5C%20T%28e_3%29%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx_1%26x_2%26x_3%5C%5C-%26%26x_n%5Cend%7Barray%7D%5Cright%5D)
becomes
![Ax = [T(e_1)\ T(e_2)\ T(e_3)]\left[\begin{array}{c}x_1&x_2&x_3\\-&&x_n\end{array}\right]](https://tex.z-dn.net/?f=Ax%20%3D%20%5BT%28e_1%29%5C%20T%28e_2%29%5C%20T%28e_3%29%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx_1%26x_2%26x_3%5C%5C-%26%26x_n%5Cend%7Barray%7D%5Cright%5D)
The x on both sides cancel out; and, we're left with:
![A = [T(e_1)\ T(e_2)\ T(e_3)]](https://tex.z-dn.net/?f=A%20%3D%20%5BT%28e_1%29%5C%20T%28e_2%29%5C%20T%28e_3%29%5D)
Recall that:
![T(e_1) = (1,2)](https://tex.z-dn.net/?f=T%28e_1%29%20%3D%20%281%2C2%29)
![T(e_2) = (-4,6)](https://tex.z-dn.net/?f=T%28e_2%29%20%3D%20%28-4%2C6%29)
![T(e_3) = (2,-6)](https://tex.z-dn.net/?f=T%28e_3%29%20%3D%20%282%2C-6%29)
In matrix:
is represented as: ![\left[\begin{array}{c}a\\b\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Da%5C%5Cb%5Cend%7Barray%7D%5Cright%5D)
So:
![T(e_1) = (1,2) = \left[\begin{array}{c}1\\2\end{array}\right]](https://tex.z-dn.net/?f=T%28e_1%29%20%3D%20%281%2C2%29%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D1%5C%5C2%5Cend%7Barray%7D%5Cright%5D)
![T(e_2) = (-4,6)=\left[\begin{array}{c}-4\\6\end{array}\right]](https://tex.z-dn.net/?f=T%28e_2%29%20%3D%20%28-4%2C6%29%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D-4%5C%5C6%5Cend%7Barray%7D%5Cright%5D)
![T(e_3) = (2,-6)=\left[\begin{array}{c}2\\-6\end{array}\right]](https://tex.z-dn.net/?f=T%28e_3%29%20%3D%20%282%2C-6%29%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D2%5C%5C-6%5Cend%7Barray%7D%5Cright%5D)
Substitute the above expressions in ![A = [T(e_1)\ T(e_2)\ T(e_3)]](https://tex.z-dn.net/?f=A%20%3D%20%5BT%28e_1%29%5C%20T%28e_2%29%5C%20T%28e_3%29%5D)
![A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-4%262%5C%5C2%266%26-6%5Cend%7Barray%7D%5Cright%5D)
Hence, the standard of the matrix A is:
![A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-4%262%5C%5C2%266%26-6%5Cend%7Barray%7D%5Cright%5D)
Answer: It's 48%. See below.
Step-by-step explanation:
By definition, percent means out of a hundred. For instance, 10 percent is 10 out of 100.
One way to make
a percent is by making the denominator 100. In order to do so, multiply the numerator and the denominator by 4, since 25 times 4 is 100.
=
= 48 %
This is very simple, and mental math is definitely possible. Hope this help.