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stealth61 [152]
3 years ago
8

I need help with Task 1 for now! Will give brainliest and 5 stars :)

Mathematics
1 answer:
Kobotan [32]3 years ago
3 0
What is task 1??????
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What are the explicit equation and domain for an arithmetic sequence with a first term of 5 and a second term of 2? (5 points)
tiny-mole [99]
The third choice is appropriate.
  an = 5 - 3(n - 1); all integers n ≥ 1

_____
This equation follows the form for the general term of an arithmetic sequence.
  an = a1 + d(n - 1)
where a1 is the first term (corresponding to n=1), and d is the common difference. From the problem statement, a1 = 5 and d = 2 - 5 = -3.
6 0
3 years ago
The table shows some values of a function of the form y = ax2 + bx + c.
natali 33 [55]

Answer:

Value of constant term c is (-4)

Step-by-step explanation:

The given table represents a function which is in the form of a quadratic equation,

y = ax² + bx + c

We choose three points (3, -10), (4, -16) and (5, -24) from the table and satisfy the equation to get the values of a, b, and c.

For point (3, -10)

-10 = a(3)² + 3b + c

9a + 3b + c = -10 -------(1)

For point (4, -16)

-16 = a(4)² + 4b + c

16a + 4b + c = -16 ------(2)

For point (5, -24)

-24 = a(5)² + 5b + c

25a + 5b + c = -24 -----(3)

Equation (1) - equation (2)

(9a + 3b + c) - (16a + 4b + c) = -10 + 16

-7a - b = 6

7a + b = -6 ------(4)

Equation (2) - equation (3)

(16a + 4b + c) - (25a + 5b + c) = -16 + 24

-9a - b = 8

9a + b = -8 -------(5)

Equation (4) - Equation (5)

(7a + b) - (9a + b) = -6 + 8

-2a = 2

a = -1

From equation (4),

-7(1) + b = -6

b = -6 + 7

b = 1

From equation (1)

9(-1) + 3(1) + c = -10

-9 + 3 + c = -10

c = -10 + 6

c = -4

Therefore, the value of constant term c is (-4).

5 0
3 years ago
CAN SOMEONE PLEASE HELP ME ASAP ITS A EXAM
Tomtit [17]

Answer:

A

Step-by-step explanation:

i did it

8 0
3 years ago
Read 2 more answers
How many ordered pairs of positive integers satisfy xY=32?
IRINA_888 [86]

Answer:


Step-by-step explanation:

xy = 32

x ; y is the divisor of 32

but : 32 =  2^5

6  ordered pairs of positive integers satisfy xY=32

(1;32) , (2;16) , (4; 8),(32; 1) , (16;2) , (8;4) .

4 0
3 years ago
Find f(k - 1) when f(x) = 5x^2+ 4x – 5.
bekas [8.4K]

Plug in k-1 to each x in the function.

f(k-1)=5(k-1)^2+4(k-1)-5

f(k-1)=5(k^2-2k+1)+4k-4-5

f(k-1)=5k^2-10k+5+4k-4-5

f(k-1)=5k^2-6k-4

Hope this helps.

頑張って!

5 0
3 years ago
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