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wlad13 [49]
3 years ago
15

Shen’s mother gave him $10 to go buy groceries. He picked up a gallon of milk for $3.49, three pounds of oranges that cost $1.14

per pound, and a box of cereal for $3.46. Shen used front-end estimation to determine whether he had enough money for the groceries. How much did he estimate the total cost would be?
He estimated that he had about $7 worth of groceries.
He estimated that he had about $9 worth of groceries.
He estimated that he had about $10.30 worth of groceries.
He estimated that he had about $10.40 worth of groceries.
Mathematics
1 answer:
garik1379 [7]3 years ago
7 0

Answer:

He estimated that he had about $10.40 worth of groceries.

Step-by-step explanation:

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The maximum number of palettes that the elevator can carry in one trip is 5.

425 times 5= 2,125+ 195= 2,320


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How much dose acute angle have
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Less than 90 degrees
8 0
2 years ago
In a class of 20 students, 40% are boys. 25% of the boys and 50% of the girls wear glasses. How many students wear glasses?
fredd [130]
Calcualate 40% (0.40) times 20 to get that there are 8 boys in the class. The rest must be girls, so 20 - 8 gives you 12 girls. 25% (0.25) times the 8 boys gives you that 2 of the boys wear glasses. 50% (0.5) times the 12 girls tives you that 6 girls wear glasses. Add together the 2 boys and the 6 girls that wear glasses to get that a total of 8 students wear glasses.
3 0
3 years ago
a fruit delivers its fruit in two types of boxes: large and small. a delivery of 3 large boxes and 5 small boxes has a total wei
Masteriza [31]

Answer:

The weight of a small box  = 13.5 kg

The weight of 1 large box = 18.5 kg

Step-by-step explanation:

Let us assume the weight of a small box = m kg

And the weight of 1 large box  = n kg

Now, the weight of 5 small box = 5 x (weight of 1 small box) =  5 m

Also, the weight of 3 large box = 3 x (weight of 1 large box) =  3 n

Here,   3 large boxes +  5 small boxes =  of 123 kilograms

⇒ 5  m + 3 n = 123   .... (1)

Again, the weight of 2 small box = 2 x (weight of 1 small box) =  2 m

Also, the weight of 12 large box = 12 x (weight of 1 large box) =  12 n

Here,   12 large boxes +  2 small boxes =  249 kilograms

⇒ 2 m+ 12 n = 249   .... (2)

Now, solving both the given equations by ELIMINATION, we get:

5  m + 3 n = 123     x (2)

2 m+ 12 n = 249     x (-5)

we get the new set of equitation as:

10 m + 6 n = 246

- 10 m - 60 n =  -1245

Adding both equation, we get

-54 n = 999

or, n = 18.5

Now, 5  m + 3 n = 123

So, 5 m = 123  -3 (18.5)  = 123 - 55.5 =  67.5

⇒  m = 13.5

Hence,  the weight of a small box = m kg = 13.5 kg

And the weight of 1 large box = n kg  = 18.5 kg

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