There are a lot of numbers you can think of, for example, 1030, or even 9939, but I don't recommend you put that ;)
Answer:
Set A's standard deviation is larger than Set B's
Step-by-step explanation:
Standard deviation is a measure of variation. One way to judge the value of standard deviation is by looking at the range of the data. In general, a dataset with a smaller range will have a smaller standard deviation.
The range of data Set A is 25-1 = 24.
The range of data Set B is 18-8 = 10.
Set A's range is larger, so we expect its standard deviation to be larger.
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The standard deviation is the root of the mean of the squares of the differences from the mean. In Set A, the differences are ±12, ±11, ±10. In Set B, the differences are ±5, ±3, ±1. We don't actually need to compute the RMS difference to see that it is larger for Set A.
Set A's standard deviation is larger than Set B's.
Answer:
The possible parking lengths are 45.96 feet and 174.031 feet
Step-by-step explanation:
Let x be the length of rectangular plot and y be the breadth of rectangular plot
A rectangular parking lot must have a perimeter of 440 feet
Perimeter of rectangular plot =2(l+b)=2(x+y)=440
2(x+y)=440
x+y=220
y=220-x
We are also given that an area of at least 8000 square feet.
So, ![xy \leq 8000](https://tex.z-dn.net/?f=xy%20%5Cleq%208000)
So,![x(220-x) \leq 8000](https://tex.z-dn.net/?f=x%28220-x%29%20%5Cleq%208000)
![220x-x^2 \leq 8000](https://tex.z-dn.net/?f=220x-x%5E2%20%5Cleq%208000)
So,![220x-x^2 = 8000\\-x^2+220x-8000=0](https://tex.z-dn.net/?f=220x-x%5E2%20%3D%208000%5C%5C-x%5E2%2B220x-8000%3D0)
General quadratic equation : ![ax^2+bx+c=0](https://tex.z-dn.net/?f=ax%5E2%2Bbx%2Bc%3D0)
Formula : ![x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%20%5Cpm%20%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
![x=\frac{-220 \pm \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=\frac{-220 + \sqrt{220^2-4(-1)(-8000)}}{2(-1)} , \frac{-220 - \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=45.96,174.031](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-220%20%5Cpm%20%5Csqrt%7B220%5E2-4%28-1%29%28-8000%29%7D%7D%7B2%28-1%29%7D%5C%5Cx%3D%5Cfrac%7B-220%20%2B%20%5Csqrt%7B220%5E2-4%28-1%29%28-8000%29%7D%7D%7B2%28-1%29%7D%20%2C%20%5Cfrac%7B-220%20-%20%5Csqrt%7B220%5E2-4%28-1%29%28-8000%29%7D%7D%7B2%28-1%29%7D%5C%5Cx%3D45.96%2C174.031)
So, The possible parking lengths are 45.96 feet and 174.031 feet
Answer:
you can use a graph like a bar graph or a pie chart. or a table that has two parts like what is linked. make sure for the graph to have a key
Step-by-step explanation:
The answer is 95.4525 percent because you would use an equation
n!/(r!(n-r)! x (P)^x * (1-P)^(n-x)
Plug in the number correspondingly
N= 10
R= 1 , 2 , 3 , 4 , 5 , 6 (You will have to do each individual, if you have a Ti-nspire calculator however there is a built program called binomialcdf.
P= .37
x = r
After plugging this is the achieved answer is 95.4525
(.0578 + .1529 + .2394 + .2461 + .1734 + .0849) x 100
additive may be a little off due to rounding.