Complete a table with at least 5 points then graph the following quadratic on the coordinate plane. Identify all zeros.y = -2x2
+ 5x + 8
1 answer:
Answer:
See attached
Step-by-step explanation:
Given function:
- y = -2x² + 5x + 8
Table and graph are attached
Zeros are included in the graph
<u>Zero's are obtained:</u>
x = 0 ⇒ y = 8
y = 0 ⇒ Solving quadratic equation
- -2x² + 5x + 8 = 0
- x = (-5 ± √(25 + 2*4*8))/-4
- x = 3.608
- x = -1.108
So zeros are (0, 8), (3.608, 0) and (-1.108, 0)
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Answer:
C. x³+10x²−5x+5
E. 7x⁵+4x²
F. x+8
Step-by-step explanation:
The graph they described should look something like the one i drew below.
So all you have to do is look at the number with the highest exponent.
If the exponent is an odd number and the x is positive then that function will have an end behavior like the picture i posted.
x³ is good
-x³ is bad because of the negative sign
x² is bad because exponent is even
x⁷ is good
123x¹ is good
