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kicyunya [14]
3 years ago
10

PLease help! Thanks

Mathematics
1 answer:
My name is Ann [436]3 years ago
8 0
Count how many times you have to move the decimal point to move it past the first number. in this case 6, so...

1.84*10^-6 is the answer.

Hope this helps! :)
You might be interested in
Help ASAP!!! A cayenne pepper stalk produces 4 peppers without adding fertilizer. The agriculture department establishes that th
LiRa [457]

1. For every ounce of fertilizer 2.5 more pepper pods can be expected.

2. When no fertilizer is added, 4 pepper pods can be expected.

3. 8 pepper pods. Plug in 1.6 for X: y=2.5(1.6)+4=8

8 0
3 years ago
Read 2 more answers
Vikram drinks 6/10 of a liter of water after gym class and 33/100 hours of a liter of juice with
algol13

The Vikram is not correct as he said that he drank a total of 39/100

of a liter in gym class and in his lunch, but he drank a total of 39/100 of a liter.

<h3>What is the fraction number?</h3>

A fraction number is the number which is a part of a whole number. It is written with a numerator and denominator. Fraction number are written as,

\dfrac{a}{b}

Here (a) is the numerator and (b) is the denominator.

Vikram drinks 6/10 of a liter of water after gym class and 33/100 hours of a liter of juice with his lunch.

Thus, the total amount he drank is,

n=\dfrac{6}{10}+\dfrac{33}{100}\\

Take the LCM 100, to solve it further,

n=\dfrac{60+33}{100}\\n=\dfrac{99}{100}\\

Now, Vikram says he drank a total of 39/100 of a liter, which is an incorrect claim.

Thus, the Vikram is not correct as he said that he drank a total of 39/100

of a liter in gym class and in his lunch, but he drank a total of 39/100 of a liter.

Learn more about the fraction number here:

brainly.com/question/78672

#SPJ1

4 0
2 years ago
the mean monthly rent for a sample of studio apartments in one city is $1260 with a standard deviation of $230. the monthly rent
il63 [147K]

Answer:

$1743, $1973, $1789 and $685 are unusual data values. $1973 is very unusual data value.

Step-by-step explanation:

The data values will be unusual if the data values more than 2 standard deviations away from mean.

mean=1260

standard deviation=230

mean-2*standard deviation

1260-2*230

800

mean+2*standard deviation

1720

mean±2*standard deviation=(800,1720)

The values that don't lie in this interval will be unusual.

mean-3*standard deviation

1260-3*230

570

mean+3*standard deviation

1260+3*230

1950

mean±3*standard deviation=(570,1950)

The values that don't lie in this interval will be very unusual.

$1099 lies in the interval mean±2*standard deviation and so it is within the two standard deviation away from mean. So, $1099 is not unusual.

$1651 lies in the interval mean±2*standard deviation and so it is within the two standard deviation away from mean. So, $1651 is not unusual.

$1743 don't lie in the interval mean±2*standard deviation and so it is more than the two standard deviation away from mean. So, $1743 is unusual.

$1973 don't lie in the interval mean±2*standard deviation and so it is more than the two standard deviation away from mean. So, $1973 is unusual. Also,  $1973 don't lie in the interval mean±3*standard deviation and so it is more than the three standard deviation away from mean. So, $1973 is very unusual.

$846 lies in the interval mean±2*standard deviation and so it is within the two standard deviation away from mean. So, $846 is not unusual.

$1789 don't lie in the interval mean±2*standard deviation and so it is more than the two standard deviation away from mean. So, $1789 is unusual.

$1398 lies in the interval mean±2*standard deviation and so it is within the two standard deviation away from mean. So, $1398 is not unusual.

$685 don't lie in the interval mean±2*standard deviation and so it is more than the two standard deviation away from mean. So, $685 is unusual.

5 0
4 years ago
(-1)x^{2} 299 cual es el resultado y los pasos?
GuDViN [60]
Answer: 299x^2 I think I hope we help you
7 0
3 years ago
Can someone help me algebra 1
ANEK [815]
Yes I can but what’s the question???
7 0
3 years ago
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