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3 years ago

How many 3/4 cup servings are in 7/8 cup of pudding

Mathematics

1 answer:

inysia [295]3 years ago

8 0

Answer:

Step-by-step explanation:

7/8 ÷ 3/4 is the same as saying 7/8 • 4/3

answer: 1.2 or 1 1/5 or 6/5

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No work need to be shown.

s344n2d4d5 [400]

This problem is quite simple, but it may seem tricky at first.
y is a function of x, so replace y with f(x)
You get f(x) = 2x - 4
D is your answer.
Have an awesome day! :)

4 0

3 years ago

Given that the average rate of change for y = f(x) over the interval [0,3] is −1, the average rate of change over the interval [

Svet_ta [14]

Answer:

Answer is 2

Step-by-step explanation:

We know that average rate of change of a function f(x) in the interval (a,b) is

$\frac{1}{b-a} \int\limits^a_b {f(x)} \, dx$

Using this we can say that

$\int\limits^0_3 {f(x)} \, dx =-1(3)=-3\\\int\limits^2_3 {f(x)} \, dx =5(1)=5\\\\\int\limits^2_6 {f(x)} \, dx =4(5)=20\\$

Using properties of integration we have

3 to 6 integral = 20-5 =15

0 to2 integral = -3=5 =-8

Thus integral form 0 to 6 would be = -8+15+5 = 12

Average rate of change form 0 to 6 = $\frac{12}{6} =2$

Answer is 2

7 0

3 years ago

The ordered pair (3,9) is located in what quadrant? Quadrant I Quadrant II Quadrant III Quadrant IV 2 points QUESTION 2 If you m

galben [10]

For the first question the answer would be the first quadrant

8 0

3 years ago

Read 2 more answers

Can you help me please 3-4 please hurry

Arte-miy333 [17]

Answer:

3) m = 18

4) p = 2

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

In 5 minutes a conveyor belt moves 300 pounds of receyclable aluminum from the delievery truck a smaller belt moves the same qua

ladessa [460]

Answer:

It will take 3.214 minutes.

Step-by-step explanation:

It is given that, the conveyor belt transports 300 cans in 5 mins and the smaller belt transports 300 cans in 9 minutes.

Thus , the speed of conveyor belt is,

= $\frac{300}{5} = 60 cans per minute$

and of smaller belt is,

= $\frac{300}{9} = \frac{100}{3} cans per minute$

Thus, when both are used together,

conveyor belt will transport (60)(t) cans and smaller belt will transport $( \frac{100}{3})$ (t) cans per minute.

Thus the equation becomes,

$300 = (60)(t) + (\frac{100}{3})(t) = (\frac{280}{3})(t)$

t = $\frac{(300)(3)}{280} = \frac{45}{14} = 3.214 minutes$

3 0

2 years ago