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2 years ago

What is the circumference of the circle 5 in

Mathematics

1 answer:

Ganezh [65]2 years ago

8 0

Answer:

The circumference of this circle is 10pi inches, which is roughly 31.4 inches.

Step-by-step explanation:

Use the formula for circumference. C= 2*radius*pi.

2*5*pi=10pi

pi=3.14, so multiply that by 10

3.14*10=31.4 inches.

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The measurenicnt of the circumference of a circle is found to be 56 centimeters. The possible error in measuring the circumferen

BartSMP [9]

Answer:

(a) Approximate the percent error in computing the area of the circle: 4.5%

(b) Estimate the maximum allowable percent error in measuring the circumference if the error in computing the area cannot exceed 3%: 0.6 cm

Step-by-step explanation:

(a)

First we need to calculate the radius from the circumference:

$c=2\pi r\\r=\frac{c}{2\pi } \\c=8.9 cm$

I leave only one decimal as we need to keep significative figures

Now we proceed to calculate the error for the radius:

$\Delta r=\frac{dt}{dc} \Delta c\\\\\frac{dt}{dc} = \frac{1}{2 \pi } \\\\\Delta r=\frac{1}{2 \pi } (1.2)\\\\\Delta r= 0.2 cm$

$r = 8.9 \pm 0.2 cm$

Again only one decimal because the significative figures

Now that we have the radius, we can calculate the area and the error:

$A=\pi r^{2}\\A=249 cm^{2}$

Then we calculate the error:

$\Delta A= (\frac{dA}{dr} ) \Delta r\\\\\Delta A= 2\pi r \Delta r\\\\\Delta A= 11.2 cm^{2}$

$A=249 \pm 11.2 cm^{2}$

Now we proceed to calculate the percent error:

$\%e =\frac{\Delta A}{A} *100\\\\\%e =\frac{11.2}{249} *100\\\\\%e =4.5\%$

(b)

With the previous values and equations, now we set our error in 3%, so we just go back changing the values:

$\%e =\frac{\Delta A}{A} *100\\\\3\%=\frac{\Delta A}{249} *100\\\\\Delta A =7.5 cm^{2}$

Now we calculate the error for the radius:

$\Delta r= \frac{\Delta A}{2 \pi r}\\\\\Delta r= \frac{7.5}{2 \pi 8.9}\\\\\Delta r= 0.1 cm$

Now we proceed with the error for the circumference:

$\Delta c= \frac{\Delta r}{\frac{1}{2\pi }} = 2\pi \Delta r\\\\\Delta c= 2\pi 0.1\\\\\Delta c= 0.6 cm$

5 0

3 years ago

Okay yes I know it's messy it was a long stressful day lol so just check the last two, are they written right? are they even rig

nata0808 [166]

Answer:

Yes

Step-by-step explanation:

Yes it is

No 1 is correct

No 2 is correct

No 3 is correct

No 4 is correct

and what i mean by correct is you answered it correct

I hope this helps you :)

6 0

3 years ago

Read 2 more answers

In the graph above, the coordinates of the vertices of QPR are Q(3, 0), P(5, 6), and R(7, 0). If AQPR is reflected across

ozzi

Answer:

D. (7, 0)

Step-by-step explanation:

The rule for a reflection over the y-axis is (x, y) → (x, -y)

This means that the x-values stay the same while the y-values change.

Q(x, y) → (x, -y)

Q(3, 0) → (3, 0)

Q'(3, 0)

P(x, y) → (x, -y)

P(5, 6) → (5, -6)

P'(5, -6)

R(x, y) → (x, -y)

R(7, 0) → (7, 0)

R'(7, 0)

Therefore, the correct answer is D.

Hope this helps!

7 0

2 years ago

Is x = 3 a solution of the equation 3x − 5 = 4x − 9? Explain.

Vika [28.1K]

Answer:

no because on is equal to 3 when plugged in and the other is equal to 4 when plugged in.

Step-by-step explanation:

$3(3)-5=4\\4(3)-9=3$

5 0

3 years ago

A container is 24m long ,9m wide and 8m high.how many books can it holds if eachbook is 20cm long,16cm wide and 6cm thick

Contact [7]

Assuming that the container and books are rectangular, the volume of both objects can be computed with the formula V=lwh, where l is length, w is width, and h is height.
As the volume of the container is 1728 m^3, while the volume of each book is 1920 cm^3. The volume for each book is converted to in terms of meters by dividing it with 100^3. The volume for each book after this conversion is 1.92 x 10^-3 m^3.
The number of the books that can fit in the shelf is the volume of the shelf divided by the volume of the books, with the assumption that the books fit perfectly in the shelf.
With the volume of the shelf divided by the volume of the books, 900,000 books can be fitted in the shelf.

6 0

3 years ago

What is the circumference of the circle￼ 5 in

What is the circumference of the circle 5 in