Answer:2/16
Step-by-step explanation:
Answer:
The probability of getting two of the same color is 61/121 or about 50.41%.
Step-by-step explanation:
The bag is filled with five blue marbles and six red marbles.
And we want to find the probability of getting two of the same color.
If we're getting two of the same color, this means that we are either getting Red - Red or Blue - Blue.
In other words, we can find the independent probability of each case and add the probabilities together*.
The probability of getting a red marble first is:

Since the marble is replaced, the probability of getting another red is: 
The probability of getting a blue marble first is:

And the probability of getting another blue is:

So, the probability of getting two of the same color is:

*Note:
We can only add the probabilities together because the event is mutually exclusive. That is, a red marble is a red marble and a blue marble is a blue marble: a marble cannot be both red and blue simultaneously.
Marilyn's finance charge at the end of the first month will be
$991.38 × 0.199/12 = $16.44
The balance subject to the next month's finance charge will be
$991.38 +16.44 -410.00 = $597.82
The finance charge at the end of the second month will be
$597.82 × 0.199/12 = $9.91
The balance remaining after the second payment will be
$597.82 +9.91 -410.00 = $197.73
The finance charge applied at the end of the third month is
$197.73 × .199/12 = $3.28
so Marilyn can make one final payment of
$197.73 +3.28 = $201.01
to pay off the balance.
In all, Marilyn has paid 2×$410.00 +201.01 =
$1021.01 . . . . . . . . corresponds to the first choice_____
In real life, Marilyn's credit card may not accrue any finance charge until after the first statement on which the charge appears. Thus the total cost of the purchase may be only $1004.02. The attached spreadsheet shows the beginning balance and the finance charges for each month for the two different scenarios.
Answer:
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Answer:
Test statistic (t-value) of this one-mean hypothesis test is -2.422.
Step-by-step explanation:
We are given that according to a survey, the average American person watches TV for 3 hours per week. She surveys 19 New Yorkers randomly and asks them about their amount of TV each week, on average. From the data, the sample mean time is 2.5 hours per week, and the sample standard deviation (s) is 0.9 hours.
We have to test if the amount of TV in New York City is less than the national average.
Let Null Hypothesis,
:
3 {means that the amount of TV in New York City is less than the national average}
Alternate Hypothesis,
:
> 3 {means that the amount of TV in New York City is more than the national average}
The test statistics that will be used here is One-sample t-test statistics;
T.S. =
~ 
where,
= sample mean time = 2.5 hours per week
= sample standard deviation = 0.09 hours
n = sample size = 19
So, <u>test statistics</u> =
~ 
= -2.422
Therefore, the test statistic (t-value) of this one-mean hypothesis test (with σ unknown) is -2.422.