Answer:
Option B
Step-by-step explanation:
Looking at the options, option B is correct because when multiplying it by matrix A, it yields the matrix AB as follows;
First row of A multiplied by first column of matrix in option D;
(1 × -1) + (0 × 0) + (0 × 0) = -1 which corresponds to the first number on the first row of Matrix AB
Since majority of matrix AB are zero, I will just prove the ones that are not zero.
Thus;
Second row of matrix A is multiplied by second column of matrix in option D;
(0 × 0) + (-1 × -1) + (0 × 0) = 1 which is same as 2nd number on second row in matrix AB
Lastly, third row of matrix A is multiplied by third column of matrix in option D;
(0 × 0) + (0 × 0) + (1 × -1) = -1 which is same as third number in third row in matrix AB
1 to 1 odds since it has 6 numbers and half of them are greater than 3
It has 3 factors, 5 x and y
To get the type of car that Sandy can afford after 3 years, we find the future annuity of the his yearly deposits.
amount deposited by Sandy in a month is $260
amount deposited per year=260*12=$3120
time=3years
rate=7.8%
Fv of annuity= P[(1+r)^n-1]/r
substituting our values we get
Fv=3120[(1+0,078)^3-1]/0.078
=10109.06208
The value of a car he can drive is $10109.06208