Answer:
A
Explanation:
The correct answer would be <u>option A</u> - GUA-CAU-ACC
<em>Looking at the table of codons, for the amino acid Val, the first base (which is on the 1st column in the 6th row) is G while the second base (2nd column, 2nd row) is U. The third column can be any of U, C, A, or G (6th column, 4th row). Hence, GUA is plausible</em>
<em>For the amino acid His, the first base is C (1st column, 2nd row), the second is A (4th column, 4th row) while the last could be any of the 4 bases. Hence, CAU is plausible.</em>
<em>For the amino acid Thr, the first base is A (first column, 5th row), the second is C (3rd column, 2nd row) while the 3rth could be any of the 4 nucleotide bases. Hence, ACC is plausible.</em>
Therefore, the correct sequence of nucleotides for Val-His_Thr would be GUA-CAU-ACC
Answer:
1) CO₂
2) 0.2551 g
Explanation:
The balanced reactions are:
CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂
MgCO₃ + 2HCl → MgCl₂ + H₂O + CO₂
1) The gas produced is CO₂.
2) Calculate mass of CaCO₃:
(0.5236 g) (0.4230) = 0.2215 g CaCO₃
Convert to moles:
(0.2215 g CaCO₃) (1 mol / 100.1 g) = 0.002213 mol CaCO₃
Find moles of CaCO₃:
(0.002213 mol CaCO₃) (1 mol CO₂ / mol CaCO₃) = 0.002213 mol CO₂
Convert to mass:
(0.002213 mol CO₂) (44.01 g / mol) = 0.09738 g CO₂
Calculate mass of MgCO₃:
(0.5236 g) (0.5770) = 0.3021 g MgCO₃
Convert to moles:
(0.3021 g MgCO₃) (1 mol / 84.31 g) = 0.003583 mol MgCO₃
Find moles of MgCO₃:
(0.003583 mol MgCO₃) (1 mol CO₂ / mol MgCO₃) = 0.003583 mol CO₂
Convert to mass:
(0.003583 mol CO₂) (44.01 g / mol) = 0.1577 g CO₂
Total mass of CO₂:
0.09738 g CO₂ + 0.1577 g CO₂ = 0.2551 g CO₂
Phospholipids are main in membrane
Answer:
The cone releases the seeds, and they float in the wind until they reach the ground where they can germinate and grow. Some do not produce seeds, instead they use spores to reproduce.
Ex. of Spore producing plants include: mosses and ferns
