Question

(06.03 MC) A 50.0 mL sample of gas at 20.0 atm of pressure is compressed to 40.0 atm of pressure at constant temperature. What is the new volume? (4 points) Group of answer choices 0.0100 mL 0.325 mL 25.0 mL 100. mL

Answer 1

Answer:

New volume is 25.0 mL

Explanation:

Let's assume the gas sample behaves ideally.

According to combined gas law for an ideal gas-

                         $\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$

where, $P_{1}$ and $P_{2}$ represent initial and final pressure respectively

$V_{1}$ and $V_{2}$ represent initial and final volume respectively

$T_{1}$ and $T_{2}$ represent initial and final temperature (in kelvin) respectively

Here, $T_{1}=T_{2}$, $V_{1}=50.0mL$, $P_{1}=20.0atm$ and $P_{2}=40.0atm$

So, $V_{2}=\frac{P_{1}V_{1}T_{2}}{P_{2}T_{1}}=\frac{(20.0atm)\times (50.0mL)}{40.0mL}=25.0mL$

So, the new volume is 25.0 mL