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denis23 [38]
4 years ago
15

Explain the difference between cocl2 6h2o and anhydrous cobalt chloride

Chemistry
1 answer:
lana66690 [7]4 years ago
8 0
<span>Colbat (ii) which is a compound birth out of the combination of chlorine and colbat to form Cocl2.6h2o has water in it as we can see from it's chemical it's hexahydrate Anhydrous cobalt chloride as the word anhydrous clearly states , does not have water in</span>
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When reacting a solution of the following secondary hydroxyl amine with 2-butene under very high temperatures, the desired produ
Naddika [18.5K]

Answer:

Mechanism for top reaction is combustion while the side product at bottom path oximes

Explanation:

Hydroxiamine is a reducing agent that requires high temperature to combust in it'd ageous state to produced oxime while water is eliminated. The reverse is the case because the production of water during combustion I does not yield the fight result as it can e very irritating.

Increased temperature stimulates the protons to become free to combust and react with 2 butene and other aldehyde during chemical reaction.

8 0
3 years ago
It is 762 miles from here to Chicago. An obese physics teacher jogs at a rate of 5.0 miles every 20.0 minutes. How long would it
Lina20 [59]

Answer:

3,048 minutes

Explanation:

762 divided by 5

that number times 20

5 0
3 years ago
14. An enzyme-catalyzed reaction was carried out with the substrate concentration initially a thousand times greater than the Km
emmainna [20.7K]

Answer:

27 min

Explanation:

The kinetics of an enzyme-catalyzed reaction can be determined by the equation of Michaelis-Menten:

v = \frac{vmax[S]}{Km + [S]}

Where v is the velocity in the equilibrium, vmax is the maximum velocity of the reaction (which is directed proportionally of the amount of the enzyme), Km is the equilibrium constant and [S] is the concentration of the substrate.

So, initially, the velocity of the formation of the substrate is 12μmol/9min = 1.33 μmol/min

If Km is a thousand times smaller then [S], then

v = vmax[S]/[S]

v = vmax

vmax = 1.33 μmol/min

For the new experiment, with one-third of the enzyme, the maximum velocity must be one third too, so:

vmax = 1.33/3 = 0.443 μmol/min

Km will still be much smaller then [S], so

v = vmax

v = 0.443 μmol/min

For 12 μmol formed:

0.443 = 12/t

t = 12/0.443

t = 27 min

7 0
3 years ago
Which sample is a pure substance?
Sunny_sXe [5.5K]
A test tube of zinc oxide
6 0
3 years ago
Read 2 more answers
`Remember that an acid is something that donates hydrogen ions. So, when considering the formula HC2H3O2 (acetic acid), which of
tiny-mole [99]

Answer:

The H in the carboxyl group.

Explanation:

Acetic acid can be written as CH₃COOH, where -COOH is the functional group carboxyl, responsible for the acidity of organic acids. The H in the carboxyl group is the one that is donated in the acid reaction.

CH₃COOH(aq) + H₂O(l) ⇄ CH₃COO⁻(aq) + H₃O⁺

Acetic acid is a weak acid, so just a small fraction of the molecules undergo this reaction to donate their hydrogen.

5 0
3 years ago
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