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Olin [163]
3 years ago
15

Identify the number of significant figures in each measurement. Type the correct answer in each box. Use numerals instead of wor

ds.

Chemistry
2 answers:
Natalka [10]3 years ago
6 0

Answer:

92

98

35

35

Explanation:

Andrei [34K]3 years ago
5 0
............
92
98
35
35
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Help anyone please ;)<br> will mark brainliest!!<br> thank you lol &lt;3
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Answer:

The answer to your question is below

Explanation:

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5 0
3 years ago
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Two compounds are standing at the same temperature. Compound "A" is evaporating more slowly than compound "
Tju [1.3M]
I believe the answer is compound B may have a lower molecular weight compared to compound A. 
At the same temperature, lighter particles of a compound have a higher average speeds than do heavier particles of another compound. Thus, particles of compound B are lighter than those of compound A and thus they have a higher average speed, hence evaporating faster compared to compound A.
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3 years ago
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Does acid in your stomach make you unhealthy?
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8 0
3 years ago
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How does the density of a gas depend on the molar mass of the gas?
AlladinOne [14]

Answer:

The density of the ideal gas is directly proportional to its molar mass.

Explanation:

Density is a scalar quantity that is denoted by the symbol ρ (rho). It is defined as the ratio of the mass (m) of the given sample and the total volume (V) of the sample.

\rho = \frac{m}{V}                          ......equation (1)

According to the ideal gas law for ideal gas:

PV = nRT                                       ......equation (2)

Here, V is the volume of gas, P is the pressure of gas, T is the absolute temperature, R is Gas constant and n is the number of moles of gas

As we know,

The number of moles: n = \frac{m}{M}

where m is the given mass of gas and M is the molar mass of the gas

So equation (2) can be written as:

PV = \frac{m}{M}RT

⇒ PM= \frac{m}{V} RT

⇒ \frac{PM}{RT}= \frac{m}{V}             ......equation (3)

Now from equation (1) and (3), we get

\frac{PM}{RT}= \frac{m}{V} = \rho  

⇒ Density of an ideal gas: \rho = \frac{PM}{RT}  

⇒ <em>Density of an ideal gas: ρ ∝ molar mass of gas: M</em>

<u>Therefore, the density of the ideal gas is directly proportional to its molar mass. </u>

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3 years ago
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