Answer:
it must also have the root : - 6i
Step-by-step explanation:
If a polynomial is expressed with real coefficients (which must be the case if it is a function f(x) in the Real coordinate system), then if it has a complex root "a+bi", it must also have for root the conjugate of that complex root.
This is because in order to render a polynomial with Real coefficients, the binomial factor (x - (a+bi)) originated using the complex root would be able to eliminate the imaginary unit, only when multiplied by the binomial factor generated by its conjugate: (x - (a-bi)). This is shown below:
where the imaginary unit has disappeared, making the expression real.
So in our case, a+bi is -6i (real part a=0, and imaginary part b=-6)
Then, the conjugate of this root would be: +6i, giving us the other complex root that also may be present in the real polynomial we are dealing with.
Answer:
a) 1st and 2nd
b) 4th one
Step-by-step explanation:
Answer:
Katherine: 920
Crystal: 552
Step-by-step explanation:
The total amount earned by each is 1472
The ratio of the earnings is Katherine / Crustal = 5/3
The total number of shares = 5 + 3 = 8
So the proportion for Katherine
5/8 = x / 1472 Cross multiply
8x = 5 * 1472
8x = 7360
x = 7360/8
x = 920
And the proportion for Crystal is
3/8 = x / 1472 Cross multiply
8x = 3 * 1472
8x = 4416
x = 4416 / 8
x = 552