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LenKa [72]
3 years ago
14

How many 1/2 cup servings are there in 7/8 cup of peanut butter

Mathematics
1 answer:
Semmy [17]3 years ago
4 0
You must be Divide with fractions.

7/8/1/2 then flip with 1/2 to 2/1 and multiply.

And the answer is 1 and 3/4

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If set A has 4 elements and B has 3 elements then set n(AXB) is a) 12 b) 14 c) 24 d) 7
Karo-lina-s [1.5K]

Answer:

The correct option is a.

Step-by-step explanation:

Given information:

Number of elements in set A = 4

Number of elements in set B = 3

We need to find n(A × B). It means we have to find the number of elements in set A × B.

If P and Q are two sets with elements m and n respectively, then the number of element in the set P × Q is m × n.

n(A\times B)=n(A)\times n(B)

n(A\times B)=4\times 3

n(A\times B)=12

The value of n(A × B) is 12. Therefore the correct option is a.

8 0
3 years ago
Suma a trei numere este 130. Stiind ca ele sunt invers proportionale cu numerele 2,3,4 aflati numerele
garik1379 [7]
A+b+c=130 a,b,c  ip  cu 2,3,4 2a=3b=4c=k a=k/2 b=k/3 c=k/4 k/2 + k/3+ k/4= 130  aducem la acelasi numitor (12) 6k+4k+3k=1560 13k=1560 k=120 a=120/2=60 b=120/3=40 c=120/4=30
6 0
3 years ago
Read 2 more answers
Subtract the rational expression
malfutka [58]
The correct answer is B
6 0
3 years ago
Which of these relations on the set {0, 1, 2, 3} are equivalence relations? If not, please give reasons why. (In other words, if
Delicious77 [7]

Answer:

(1)Equivalence Relation

(2)Not Transitive, (0,3) is missing

(3)Equivalence Relation

(4)Not symmetric and Not Transitive, (2,1) is not in the set

Step-by-step explanation:

A set is said to be an equivalence relation if it satisfies the following conditions:

  • Reflexivity: If \forall x \in A, x \rightarrow x
  • Symmetry: \forall x,y \in A, $if x \rightarrow y,$ then y \rightarrow x
  • Transitivity: \forall x,y,z \in A, $if x \rightarrow y,$ and y \rightarrow z, $ then x \rightarrow z

(1) {(0,0), (1,1), (2,2), (3,3)}

(3) {(0,0), (1,1), (1,2), (2,1), (2,2), (3,3)}

The relations in 1 and 3 are Reflexive, Symmetric and Transitive. Therefore (1) and (3) are equivalence relation.

(2) {(0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3)}

In (2), (0,2) and (2,3) are in the set but (0,3) is not in the set.

Therefore, It is not transitive.

As a result, the set (2) is not an equivalence relation.

(4) {(0,0), (0,1), (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3)}

(1,2) is in the set but (2,1) is not in the set, therefore it is not symmetric

Also, (2,0) and (0,1) is in the set, but (2,1) is not, rendering the condition for transitivity invalid.

5 0
3 years ago
Make a the subject of:<br> v = u + at
zmey [24]

Answer:

a =  \frac{v  - u}{t}  \:

Step-by-step explanation:

v = u + at

at = v - u

a =  \frac{v  - u}{t}

8 0
3 years ago
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