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salantis [7]
3 years ago
14

Need some help, Thank you!!! ^^

Mathematics
1 answer:
stira [4]3 years ago
4 0

Given:

3b+8\geq 14

To find:

The steps to solving the given inequality.

Solution:

We have,

3b+8\geq 14

Subtract 8 from both sides.

3b+8-8\geq 14-8

3b\geq 6

Divide both sides by 3.

\dfrac{3b}{3}\geq \dfrac{6}{3}

b\geq 2

Two steps are:

1. Subtract 8 from both sides of the inequality.

2. Divide both sides of the inequality by 3.

Therefore, the correct option is A.

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Calculate s26 for the arithmetic sequence in which a14=4.1 and the common difference is d=1.7
sweet-ann [11.9K]

Answer:

The value of s_{26}=84.5

Step-by-step explanation:

We have given  a_{14}=4.1

d=1.7

We have to find s_{26}

So, a_{14}=a+13d from the formula

a_n=a+(n-1)d

When n=14

a_{14}=a+(14-1)(1.7)=a+13(1.7)

4.1=a+22.1

-18=a

a=-18

Using the formula:

s_n=\frac{n}{2}[2a+(n-1)d

When n=26

s_{26}=\frac{26}{2}[2(-18)+(26-1)(1.7)]

On simplification we get:

s_{26}=84.5



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