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Nesterboy [21]
3 years ago
10

If you take out a loan for $4,000 and you will owe $4,920 after 2 years, what is the rate of simple interest? Express your answe

r as a percentage rounded to the nearest tenth of a percent if necessary, but do not include the percent sign.
Mathematics
2 answers:
Papessa [141]3 years ago
5 0

Answer:

11.5

Step-by-step explanation:

you have to use this equation to solve it [r = (1/t)(A/P - 1)] and basically just plug the numbers in to get 11.5. (you could also use one of those online calculators)

r = (1/2)((4920/4000) - 1) = 0.115

r = 0.115

bulgar [2K]3 years ago
3 0

Answer:

11.5

Step-by-step explanation:

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Can 3 points be Collinear
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Three and more points are collinear
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3 years ago
Read 2 more answers
three trigonometric functions for a given angle are shown below csc theta = 13/12, sec theta = -13/5, cot theta = -5/12 what are
goldenfox [79]
We have that
csc ∅=13/12
sec ∅=-13/5
cot ∅=-5/12

we know that
csc ∅=1/sin ∅
sin ∅=1/ csc ∅------> sin ∅=12/13

sec ∅=-13/5
sec ∅=1/cos ∅
cos ∅=1/sec ∅------> cos ∅=-5/13

sin ∅ is positive and cos ∅ is negative
so
∅ belong to the II quadrant

therefore
<span>the coordinates of point (x,y) on the terminal ray of angle theta are
</span>x=-5
y=12

the answer is
point (-5,12)

see the attached figure

6 0
3 years ago
Read 2 more answers
Calculate the discriminant to determine the number solutions. y = x ^2 + 3x - 10
Nataly_w [17]

1. The first step is to find the discriminant itself. Now, the discriminant of a quadratic equation in the form y = ax^2 + bx + c is given by:

Δ = b^2 - 4ac

Our equation is y = x^2 + 3x - 10. Thus, if we compare this with the general quadratic equation I outlined in the first line, we would find that a = 1, b = 3 and c = -10. It is easy to see this if we put the two equations right on top of one another:

y = ax^2 + bx + c

y = (1)x^2 + 3x - 10

Now that we know that a = 1, b = 3 and c = -10, we can substitute this into the formula for the discriminant we defined before:

Δ = b^2 - 4ac

Δ = (3)^2 - 4(1)(-10) (Substitute a = 1, b = 3 and c = -10)

Δ = 9 + 40 (-4*(-10) = 40)

Δ = 49 (Evaluate 9 + 40 = 49)

Thus, the discriminant is 49.

2. The question itself asks for the number and nature of the solutions so I will break down each of these in relation to the discriminant below, starting with how to figure out the number of solutions:

• There are no solutions if the discriminant is less than 0 (ie. it is negative).

If you are aware of the quadratic formula (x = (-b ± √(b^2 - 4ac) ) / 2a), then this will make sense since we are unable to evaluate √(b^2 - 4ac) if the discriminant is negative (since we cannot take the square root of a negative number) - this would mean that the quadratic equation has no solutions.

• There is one solution if the discriminant equals 0.

If you are again aware of the quadratic formula then this also makes sense since if √(b^2 - 4ac) = 0, then x = -b ± 0 / 2a = -b / 2a, which would result in only one solution for x.

• There are two solutions if the discriminant is more than 0 (ie. it is positive).

Again, you may apply this to the quadratic formula where if b^2 - 4ac is positive, there will be two distinct solutions for x:

-b + √(b^2 - 4ac) / 2a

-b - √(b^2 - 4ac) / 2a

Our discriminant is equal to 49; since this is more than 0, we know that we will have two solutions.

Now, given that a, b and c in y = ax^2 + bx + c are rational numbers, let us look at how to figure out the number and nature of the solutions:

• There are two rational solutions if the discriminant is more than 0 and is a perfect square (a perfect square is given by an integer squared, eg. 4, 9, 16, 25 are perfect squares given by 2^2, 3^2, 4^2, 5^2).

• There are two irrational solutions if the discriminant is more than 0 but is not a perfect square.

49 = 7^2, and is therefor a perfect square. Thus, the quadratic equation has two rational solutions (third answer).

~ To recap:

1. Finding the number of solutions.

If:

• Δ < 0: no solutions

• Δ = 0: one solution

• Δ > 0 = two solutions

2. Finding the number and nature of solutions.

Given that a, b and c are rational numbers for y = ax^2 + bx + c, then if:

• Δ < 0: no solutions

• Δ = 0: one rational solution

• Δ > 0 and is a perfect square: two rational solutions

• Δ > 0 and is not a perfect square: two irrational solutions

6 0
3 years ago
Medicine taken by a patient breaks down and eventually leaves the patient’s system. Suppose a dose of 60 milligrams (mg) of medi
jeyben [28]

Answer:

60*0.8 raised to the t power where t is time

Step-by-step explanation:

60*0.8³=30.72

60*0.8∧4.25=23.24254578

3 0
3 years ago
Factor 75t2 + 12.<br> 3(5t + 2)2<br> 3(25+2 +4)<br> 3(251-4)
frosja888 [35]

Answer:

75t^2+12=3(25t^2+4)

Option C)

Step-by-step explanation:

Here we are given with the expression 75t^2+12

The GCF of 75t^2 and 12 is 3

Hence we take 3 as GCF and bring it in front of the bracket.

3(25t^2+4)

It can not be factorise furthure  as there is no GCF of 25 and  also there is no rule for sum of squares so that we may apply it on this. Hence the answer would be

3(25t^2+4)

Option C)

4 0
3 years ago
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