Answer:
false
Step-by-step explanation:
point slope form : y - y1 = m( x - x1 )
the equation y = 1/2x - 5 does not follow this therefore the answer is false
the equation y = -1/2x - 5 is instead put in slope intercept form , y = mx + b
(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
---------------------------------------------------------------------------------------
(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.
Answer:
The second possible answer is the correct one.
Step-by-step explanation:
The second possible answer is the correct one. As x increases, 4^x increases exponentially. However, in this case there's a negative sign in front of 4^x, so we know that the graph follows an exponential trajectory downward. Also note that 4^0 = 1, so 1 - 4^x = 0 at x = 0.
Answer:
y = 6x +1
Step-by-step explanation:
To write the slope-intercept form equation for a line, you need to know the slope and the y-intercept. These can be found from their respective formulas.
__
<h3>slope</h3>
The slope of a line between points (x1, y1) and (x2, y2) is given by the formula ...
m = (y2 -y1)/(x2 -x1)
For points (-1, -5) and (0, 1), the slope is ...
m = (1 -(-5))/(0 -(-1)) = 6/1
m = 6
<h3>y-intercept</h3>
The y-intercept is the value of y where the line crosses the y-axis. That axis is where x = 0. There is a formula that can be used to find the y-intercept from the slope and a point on the line:
b = y -mx . . . . . y-intercept of line with slope m through point (x, y)
However, one of the given points is already the y-intercept: (0, 1). It tells you b=1.
<h3>equation</h3>
The slope-intercept equation is ...
y = mx +b
y = 6x +1
Answer: 0.16666666666
Step-by-step explanation:lol
