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liq [111]
3 years ago
5

The line above goes through points (-4,0) and (0,1). what is the equation of the line?​

Mathematics
1 answer:
mariarad [96]3 years ago
5 0

Answer:

y = \frac{1}{4} x + 1

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 4, 0) and (x₂, y₂ ) = (0, 1)

m = \frac{1-0}{0+4} = \frac{1}{4}

Note the line crosses the y- axis at (0, 1) ⇒ c = 1

y = \frac{1}{4} x + 1 ← equation of line

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2 years ago
(1 point) A particle starts at the point P=(−2,−1,3)P=(−2,−1,3) when t=0t=0 and moves along a straight line toward Q=(−4,0,6)Q=(
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Answer:

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Step-by-step explanation:

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