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liq [111]
3 years ago
5

The line above goes through points (-4,0) and (0,1). what is the equation of the line?​

Mathematics
1 answer:
mariarad [96]3 years ago
5 0

Answer:

y = \frac{1}{4} x + 1

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 4, 0) and (x₂, y₂ ) = (0, 1)

m = \frac{1-0}{0+4} = \frac{1}{4}

Note the line crosses the y- axis at (0, 1) ⇒ c = 1

y = \frac{1}{4} x + 1 ← equation of line

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chubhunter [2.5K]

Answer:

y = 3x + 6

Step-by-step explanation:

The domain is you x values. You need to substitute the x values into both functions to see which one produces the plots on the graph.

<h3>y = 2x + 4</h3>

when x = -3, y = 2(-3) + 4 = -6 + 4 = -2

when x = -2, y = 2(-2) + 4 = = -4 + 4 = 0

when x = -1, y = 2(-1) + 4 = = -2 + 4 = 2

when x = -0, y = 2(0) + 4 = 0 + 4 = 4

<h3>y = 3x + 6</h3>

when x = -3, y = 3(-3) + 6 = -9 + 6 = -3

when x = -2, y = 3(-2) + 6 = = -6 + 6 = 0

when x = -1, y = 3(-1) + 6 = = -3 + 6 = 3

when x = -0, y = 3(0) + 6 = 0 + 6 = 6

The points on the graph are (-3, -3), (-2, 0), (-1, 3) and (0, 6)

This is same as the results from the function y = 3x + 6

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3 years ago
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