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castortr0y [4]
3 years ago
5

Heeeeeelllllllllppppppppppppppppp mmmmmmmmeeeeeeeeeeee!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
8 0

Yes it is possible for a geometric sequence to not outgrow an arithmetic one, but only if the common ratio r is restricted by this inequality: 0 < r < 1

Consider the arithmetic sequence an = 9 + 2(n-1). We start at 9 and increment (or increase) by 2 each time. This goes on forever to generate the successive terms.

In the geometric sequence an = 4*(0.5)^(n-1), we start at 4 and multiply each term by 0.5, so the next term would be 2, then after that would be 1, etc. This sequence steadily gets closer to 0 but never actually gets there. We can say that this is a strictly decreasing sequence.

If your teacher insists that the geometric sequence must be strictly increasing, then at some point the geometric sequence will overtake the arithmetic one. This is due to the nature that exponential growth functions grow faster compared to linear functions with positive slope.

You might be interested in
How to you solve -15=y-62
sdas [7]
First move the (Y) to the other side of the equal sign,
- y - 15 = - 62
Then subtract add (15) on both sides
- y = - 47
Since a variable can't be negative just divide by (-1) on both sides,
\frac{ - y}{ - 1} = \frac{ - 47}{ - 1}
The answer would be,
y = 47
Hope this helped
:D
7 0
2 years ago
Clara and Toby are telemarketers.
Korolek [52]

Answer:

Toby will reach more people in 40 phone calls

3 0
2 years ago
In triangle ABC, Aat the top of the triangle, B at 90° and C at the third end, angle C = 21°, the hypotenus = 15m,find BC = y th
dsp73

Answer

Step-by-step explanation:

Law of sines: SinB/15 = SinA/BC

B = 90

A = 180-90-21=69°

BC= (15*SinA)/SinB = (15*sin69)/1 ≈ 14m

7 0
2 years ago
katie collets stamp she has stamps from canada, United Staes,ands Rest of the world in a ratio of 1:1.2:1.5 she has 135 stamps f
lyudmila [28]

Answer:

90 stamps from Canada, 108 stamps from the United States, and 135 stamps from the Rest of the World

Step-by-step explanation:

Since this is a problem of proportion we can use the Rule of three to solve this. We do this by multiplying the diagonal available values and dividing by the third value in order to get the missing variable, which in this case would be the number of stamps in the other country. Like so...

1.5  <=====>  135 stamps

1.2  <=====>  x  stamps (United States)

(1.2 * 135) / 1.5 = 108 stamps (United States)

1.5  <=====>  135 stamps

1  <=====>  x  stamps (Canada)

(1 * 135) / 1.5 = 90 stamps (Canada)

Finally, we can see that Katie had 90 stamps from Canada, 108 stamps from the United States, and 135 stamps from the Rest of the World. All creating a ratio or 1:1.2:1.5

8 0
2 years ago
Solve.
bixtya [17]

Answer:

-3 ± 2\sqrt{3} = x

Step-by-step explanation:

x² + 6x + 9 = 12 → x² + 6x - 3

Since this Quadratic Expression is unfactorable, apply the <em>Quadratic</em><em> </em><em>Formula</em>:

x = -b ± \frac{\sqrt{{b}^{2} - 4ac}}{2a}

-6 ± \frac{\sqrt{{6}^{2} - 4(1)(-3)}}{2(1)} =   -6 ± \frac{\sqrt{36 + 12}}{2} = -6 ± \frac{\sqrt{48}}{2} \\ \\ -3 ± 2\sqrt{3}

√48 = √[3 × 16] = 4√3

½[4√3] = 2√3

Then attach half of -6 to it as well [-3]:

-3 ± 2√3

I am joyous to assist you anytime.

7 0
3 years ago
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