Hey there!
Let's set up our expression:
(7a-6b+7)-(8a-2)
In order to simplify, we can use that subtraction sign and distribute it, using the distributive property. We have:
7a-6b+7-8a+2
Notice how it's plus two, because a negative times a negative two is a positive two. Now, it's a matter of finding the like terms and adding or subtracting them. These like terms can either have no variable, or have different coefficients but the same variable. That means our like terms are the 7a and -8a, and the 7 and 2. There's no like term for the 6b. That means we have:
(7a-8a) - 6b + (7+2) =
-a - 6b + 9
Hope this helps!
Answer:
b b.b b b b b b b b b b b b b b b b b b
Step-by-step explanation:
b b b
1/2 times 6 = 1/2 * 6
so in order to make this multiplication you have to turn 6 to a fraction, 6 is equal to 6/1
so , the way to multiply them is multiply the top with the top and it will be the top in the answer and the exact same with the bottoms
6*1= 6
2*1=2
so the fraction is 6/2, since a fraction is basicly a division
6/2 = 3
so the answer to your question is 3
i hope i helped you
From the given figure ,
RECA is a quadrilateral
RC divides it into two parts
From the triangles , ∆REC and ∆RAC
RE = RA (Given)
angle CRE = angle CRA (Given)
RC = RC (Common side)
Therefore, ∆REC is Congruent to ∆RAC
∆REC =~ ∆RAC by SAS Property
⇛CE = CA (Congruent parts in a congruent triangles)
Hence , Proved
<em>Additional</em><em> comment</em><em>:</em><em>-</em>
SAS property:-
"The two sides and included angle of one triangle are equal to the two sides and included angle then the two triangles are Congruent and this property is called SAS Property (Side -Angle-Side)
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Consider the proof. Given: Segment AB is parallel to line DE. Prove: AD/DC = BE/EC What is the missing statement in Step 5? A.) AC = BC B.) AC/DC = BC/EC C.) AD...
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Answer:
D
Step-by-step explanation:
Thats is your answer. Have a good day