Answer:
- P(t) = 100·2.3^t
- 529 after 2 hours
- 441 per hour, rate of growth at 2 hours
- 5.5 hours to reach 10,000
Step-by-step explanation:
It often works well to write an exponential expression as ...
value = (initial value)×(growth factor)^(t/(growth period))
(a) Here, the growth factor for the bacteria is given as 230/100 = 2.3 in a period of 1 hour. The initial number is 100, so we can write the pupulation function as ...
P(t) = 100·2.3^t
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(b) P(2) = 100·2.3^2 = 529 . . . number after 2 hours
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(c) P'(t) = ln(2.3)P(t) ≈ 83.2909·2.3^t
P'(2) = 83.2909·2.3^2 ≈ 441 . . . bacteria per hour
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(d) We want to find t such that ...
P(t) = 10000
100·2.3^t = 10000 . . . substitute for P(t)
2.3^t = 100 . . . . . . . . divide by 100
t·log(2.3) = log(100)
t = 2/log(2.3) ≈ 5.5 . . . hours until the population reaches 10,000
Answer:
a and d is the correct answer
Step-by-step explanation:
Answer:
Step-by-step explanation:
Number of bags = Total money spent / Cost of each bag
x = number of bags of chips
Simply divide 17.50 by 1.25 to work out how many bags of chips he can purchase.
Number of bags = Total money spent / Cost of each bag
= ?
Answer:
The rate of the volume increase will be 
Step-by-step explanation:
Let's take the derivative with respect to time on each side of the volume equation.
Now, we just need to put all the values on the rate equation.
We know that:
dR/dt is 0.04 cm/s
And we need to know what is dV/dt when R = 10 cm.
Therefore using the equation of the volume rate:
I hope it helps you!
The 13 stripes alternate red and white: 7 red and 6 white.
Each of 13 stripes is (39 in. / 13) = 3 in. wide.
4 of the 7 red stripes are 39 in. long. The other 3 are 65 in. long.
The total area (l*w) of the flag is (65 in.)*(39 in.)=2535 sq. in.
The red stripes make up an area (l*w) that is:
4*(area of short stripes) + 3*(area of long stripes)
Red area is 4*(39*3) + 3*(65*3) = 1053 sq in.
The fraction of the flag that is red is:
1053 sq. in. / 2535 sq. in.
