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DIA [1.3K]
3 years ago
7

(20 points)

Mathematics
1 answer:
Nikolay [14]3 years ago
6 0

The excluded values are the values that the variable cannot take on because it makes the overall expression undefined.

For example, we can't have x=0 in the expression \dfrac1x because \dfrac10 is undefined.

For both of these problems you do the same sort of thing, with some factorization along the way:

\dfrac{9p^2}{4p^2-12p}=\dfrac{9p^2}{4p(p-3)}

If p=0 or p=3, the denominator is 0 and we have an undefined expression, so these are the excluded values.

\dfrac6{m^2+m-42}=\dfrac6{(m+7)(m-6)}

If m=-7 or m=6, we get an undefined expression.

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