The required probability is 
<u>Solution:</u>
Given, a shipment of 11 printers contains 2 that are defective.
We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.
Now, we know that, 
Probability for first draw to be non-defective 
(total printers = 11; total defective printers = 2)
Probability for second draw to be non defective 
(printers after first slot = 10; total defective printers = 2)
Then, total probability 
Multiply the first equation by 3, and multiply the second equation by 4.
Well there are 52 cards in a deck. There are 13 of each kind of card. So 13/52 are diamonds
Absolute value is always positive, unless there is a negative sign outside of the lines
Answer:
PB=5
Step-by-step explanation:
Since you know that BD=24, you also know that both segments BC and CD have the same value since they're congruent: 12. You also were given the value of PC. Using Pythagorean Theorm, Substitute 12 for a and 13 for c, so the equation would say
12^2+b^2=13^2
Simplify to get
144+b^2=169
Now subtract 144 from 169 and you get 25. That is b^2. All you have to do now is square root 25 to isolate b.
√25=5
So therefore,
b=5
