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Oksi-84 [34.3K]
3 years ago
15

Mr.Smith bought 5 movie tickets. The total cost was $38.75. How much did each ticket cost?

Mathematics
2 answers:
lyudmila [28]3 years ago
3 0

Answer:

7.75 dollars

Step-by-step explanation:

38.75/5=

7.75 dollars

Gennadij [26K]3 years ago
3 0

Answer:

<h2>$7.75</h2>

Step-by-step explanation:

$38.75/5=$7.75

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leva [86]
In order to simplify, let's add 6x and 13x.

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3 years ago
HELP PLEASE LOTS OF POINTS!!​
masha68 [24]

Answer:

890.625

Step-by-step explanation:

2.5x2.5x2.5 (Volume of Cube)=15.625

Density is 57

57=x/15.625

890.625=x

8 0
2 years ago
C/2 - 3 + 6/d when c=14 d=3
Nataliya [291]

Answer:

6

Step-by-step explanation:

14/2 - 3 + 6/3

Divide 14 by 2 to get 7.

7−3+6/3

Subtract 3 from 7 to get 4.

4+6/3

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4+2

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6

4 0
2 years ago
There are 15 identical pens in your drawer, nine of which have never been used. On Monday, yourandomly choose 3 pens to take wit
DaniilM [7]

Answer: p = 0.9337

Step-by-step explanation: from the question, we have that

total number of pen (n)= 15

number of pen that has never been used=9

number of pen that has been used = 15 - 9 =6

number of pen choosing on monday = 3

total number of pen choosing on tuesday=3

note that the total number of pen is constant (15) since he returned the pen back .

probability of picking a pen that has never been used on tuesday = 9/15 = 3/5

probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5

probability of picking a pen that has been used on tuesday = 6/15 = 2/5

probability of not picking a pen that has not been used on tuesday= 1- 2/5= 3/5

on tuesday, 3 balls were chosen at random and we need to calculate the probability that none of them has never been used .

we know that

probability of ball that none of the 3 pen has never being used on tuesday = 1 - probability that 3 of the pens has been used on tuesday.

to calculate the probability that 3 of the pen has been used on tuesday, we use the binomial probability distribution

p(x=r) = nCr * p^{r} * q^{n-r}

n= total number of pens=15

r = number of pen chosen on tuesday = 3

p = probability of picking a pen that has never been used on tuesday = 9/15 = 3/5

q = probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5

by slotting in the parameters, we have that

p(x=3) = 15C3 * (\frac{2}{5})^{3} * (\frac{3}{5})^{12}

p(x=3) = 455 * 0.4^{3} * 0.6^{12}

p(x=3) = 455 * 0.064 * 0.002176

p(x=3) = 0.0633

thus probability that 3 of the pens has been used on tuesday. = 0.0633

probability of ball that none of the 3 pen has never being used on tuesday  = 1 - 0.0633 = 0.9337

3 0
3 years ago
What is the slope for (-6,4) and (2,12)
Romashka-Z-Leto [24]

Answer:

1

Step-by-step explanation:

(-6,4) and (2,12)

slope = m = (y2 - y1) / (x2 - x1)

= 12 - 4 / 2 - (-6)

= 8/8

= 1

5 0
3 years ago
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