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meriva
4 years ago
8

Previous

Mathematics
1 answer:
kaheart [24]4 years ago
6 0
I think the answer would be 2,570,720
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Tell whether the lines for each pair of equations are parallel, perpendicular, or neither
nevsk [136]

Answer: this will help you with this qustion and others involving graphs desmos . com


Step-by-step explanation:


6 0
3 years ago
Please help me. I don’t understand this at all...
mylen [45]
Problem 1

With limits, you are looking to see what happens when x gets closer to some value. For example, as x gets closer to x = 2 (from the left and right side), then y is getting closer and closer to y = 1/2. Therefore the limiting value is 1/2

Another example: as x gets closer to x = 4 from the right hand side, the y value gets closer to y = 4. This y value is different if you approach x = 0 from the left side (y would approach y = 1/2)

Use examples like this and you'll get the results you see in "figure 1"

For any function values, you'll look for actual points on the graph. A point does not exist if there is an open circle. There is an open circle at x = 2 for instance, so that's why f(2) = UND. On the other hand, f(0) is defined and it is equal to 4 as the point (0,4) is on the function curve.

=======================================================

Problem 2

This is basically an extension of problem 1. The same idea applies. See "figure 2" (in the attached images) for the answers. 

6 0
3 years ago
Heeelllppp me please :)
Sophie [7]
The common ratio is 3.

I hope this helps!
4 0
3 years ago
HI HELP ASAP PLEASE EXPLAIN HOW TO DO STUFF LIKE THIS PLEASE HELP
statuscvo [17]

Given:

∠A = 66°

AB = 5 mi

To find:

The distance from point B to point C.

Solution:

Using trigonometric ratio formula:

$\tan \theta=\frac{\text { Opposite side of } \theta}{\text { Adjacent side of } \theta}

$\tan A =\frac{\text { Opposite side of } A }{\text { Adjacent side of } A}

$\tan 66^\circ =\frac{BC}{AB}

$2.25 =\frac{BC}{5}

Multiply by 5 on both sides.

$5\times 2.25 =5\times \frac{BC}{5}

$11.2 = BC (nearest tenth)

The distance from point B to point C is 11.2 mi.

7 0
3 years ago
What is the slope of the line that passes through the points (-6, -8)(−6,−8) and (-14, 4) ?(−14,4)? Write your answer in simples
creativ13 [48]

Answer:

\huge\boxed{slope=-\dfrac{3}{2}}

Step-by-step explanation:

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have two points (-6, -8) and (-14, 4).

Substitute

x_1=-6,\ y_1=-8,\ x_2=-14,\ y_2=4

m=\dfrac{4-(-8)}{-14-(-6)}=\dfrac{4+8}{-14+6}=\dfrac{12}{-8}=-\dfrac{12:4}{8:2}=-\dfrac{3}{2}

8 0
4 years ago
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