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2 years ago

If I have (4,0) and (0,-2) on a graph. What would be the new points if I reflect it off the x-axis

Mathematics

1 answer:

lions [1.4K]2 years ago

5 0

Answer:

(-4,0) and (0,-2) ‹---- this would stay the same

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Jemer lost his ball and decided to buy a new one. the new ball cost $300. which is three times the price of his old ball. how mu

shusha [124]

Answer:

The cost of the old ball was $100.

Step-by-step explanation:

The cost of the new ball = $300

The new ball has three times the price of his old ball.

So, let the price of the old ball be = x

As per situation, we get the equation:

$3x=300$

Dividing both sides by 3:

$\frac{3x}{3}= \frac{300}{3}$

=> x = 100

Hence, the cost of the old ball was $100.

8 0

2 years ago

16x+4(x-5) how do I solve this.?

Nadusha1986 [10]

Answer:20x-20

16x+4(x-5)

4(x-5)=4x-20

16x+4x

20x-20

8 0

3 years ago

Read 2 more answers

P and Q are two points on the line x - y + 1 = 0 and are at distance 5 from the origin. Find the area of the triangle OPQ.

Alecsey [184]

Answer:

P and Q are two points on the line x-y+1=0 and are at a distant of 5 units from the origin. Find the area of triangle POQ.

Step-by-step explanation:

P and Q are the intersection points of

x-y+1 = 0 and the circle x^2 + y^2 = 25

sub y = x+1 into the circle

x^2 + (x+1)^2 = 25

x^2 + x^2 + 2x + 1 - 25 = 0

x^2 + x - 12 = 0

(x+4)(x-3) = 0

x = 3 or x = -4

y = 4 or y = -3

so P(3,4) and Q(-4,3) are our two points

Height of triangle.

h = |0 - 0 + 1|/√2 = 1/√2

PQ = √( (-7)^2 + 1^2) = √50 = 5√2

area POQ = (1/2)(1/√2)(5√2) = 5/2 square units

hope this helped

7 0

2 years ago

A study indicates that 37% of students have laptops. You randomly sample 30 students. Find the mean and the standard deviation o

Brilliant_brown [7]

Answer:

The mean and the standard deviation of the number of students with laptops are 1.11 and 0.836 respectively.

Step-by-step explanation:

Let X = number of students who have laptops.

The probability of a student having a laptop is, P (X) = p = 0.37.

A random sample of n = 30 students is selected.

The event of a student having a laptop is independent of the other students.

The random variable X follows a Binomial distribution with parameters n and p.

The mean and standard deviation of a binomial random variable X are:

$\mu=np\\\sigma=\sqrt{np(1-p)}$

Compute the mean of the random variable X as follows:

$\mu=np=30\times0.37=1.11$

The mean of the random variable X is 1.11.

Compute the standard deviation of the random variable X as follows:

$\sigma=\sqrt{np(1-p)}=\sqrt{30\times0.37\times(1-0.37)}=\sqrt{0.6993}=0.836$

The standard deviation of the random variable X is 0.836.

5 0

3 years ago

There are seven days how many days are there in 16 weeks

Leya [2.2K]

There are 112 days in 16 weeks because all you have too do is take 16 and multiply it by 7 which gets you 112. Hope this helped.

4 0

2 years ago

Read 2 more answers