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3 years ago

How do you do: -6(6a-5)=-2(8-5a)

Mathematics

1 answer:

devlian [24]3 years ago

7 0

Answer:

a = 1

Step-by-step explanation:

1. distribute the -6 on the left into the parentheses. you should get -36a + 30.

2. on the side right of the =, distribute the -2 to get -16 + 10a.

now it should look like -36a + 30 = -16 + 10a.

3. move the terms over to isolate the a value. subtract 30 to the right side to get -46 (-36a=-46+10a)

4. move the 10a on the right to the left by subtracting it to the other side.

(-46a=-46)

5.divide by -46 to get a=1

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(X^4+5x^2-36)(2x^2+9x-5)=0 solve for the roots. Factor both quadratic equations

iren [92.7K]

Using trial and error
x^4+5x^2-36 factors to (x-2)(x+2)(x^2+9)
2x^2+9x-5 factors to (x+5)(2x-1)
so

(x-2)(x+2)(x^2+9)(x+5)(2x-1)=0

set each to zero
x-2=0
x=2

x+2=0
x=-2

x^2+9=0
x^2=-9
x=3√-1
x=3i

x+5=0
x=-5

2x-1=0
2x=1
x=1/2=0.5

roots are
x=-5-2,0.5,2, and the imaginary root 3i

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3 years ago

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Nimfa-mama [501]

Answer:

y = $-\frac{1}{3} x$ + 2

Step-by-step explanation:

The slope of the line that has an x intercept of (2,0) and y-intercept of (0,-6) is:

Slope(s) = Change in y ÷ change in x

s = $\frac{0 - -6}{2 - 0}$ = 3

The slope of the perpendicular line to this line with slope of 3 has to have a slope of -1 ÷ 3 = $-\frac{1}{3}$

Reason: The product of slopes of lines perpendicular to each other have to be -1

So the slope of the perpendicular line that passes through (-6,4) is $-\frac{1}{3}$

As mentioned earlier, we derive a slope of a line by dividing the change in y by the change in x

Taking another point (x,y) on the line,

$-\frac{1}{3}$ = $\frac{y - 4}{x - -6}$

$-\frac{1}{3}$ = $\frac{y - 4}{x + 6}$

y - 4 = $-\frac{1}{3}$ x - 2

y = $-\frac{1}{3}$ x + 2

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2 years ago

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Delicious77 [7]

Answer: x = 8

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8x - 5x = 60-36

3x = 24

x = 24/3

x = 8

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Aloiza [94]

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Hello!

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