The equation of line passing through (0, 6) and (6, 0) is y = -x + 6
<u><em>Solution:</em></u>
Given that graph of a line passes through the points (0, 6) and (6, 0)
<em><u>The equation of line containing two points is given as:</u></em>
----- eqn 1
Where "m" is the slope of line
Here given two points are (0, 6) and (6, 0)

Let us first find the slope of line

Substituting the values we get,

Thus slope of line "m" = -1
Substituting in eqn 1

In standard form we get,
y = -x + 6
x + y = 6
Thus equation of line is found