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motikmotik
2 years ago
8

Which of the following is not a major arc? 148°

Mathematics
1 answer:
fgiga [73]2 years ago
6 0
A major arc is over 180°.. minor arcs are under 180°... I think this is right
Hope this helps
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OMG DUE IN 40 MINUTESSSS!!
ELEN [110]

Answer:

17 1/3 52/3

Step-by-step explanation:

3x+y=38

3x+2y=52

-y=14

y=-14

3x+-14=38

3x-14=38

3x=38+14

3x=52

3x/3=52/3

x=171\3

17 is a whole number then 1 divided by 3 . thus is x

4 0
2 years ago
Estimate 58% of 112 using benchmark percents. Explain your answer.
vitfil [10]

Answer:

64.96

Step-by-step explanation:

The most common benchmark percents are 0\% , 10\% , 25\% , 50\% , 75\% and 100\%

We are given 58\% which is closest to 50\%.

Now we calculate 50\% \ of \ 112 which is equal to 56.

We are left with 8\% more to add.

We can say 1\% \ of \ 112 \ is\ 1.12

Therefore 8\% \ of \ 112 \ would \ be \ 1.12\times8=8.96

Now add the two.

56+8.96= 64.96

Thus 64.96 is the answer.

3 0
3 years ago
PLEASE HELP ASAP DUE IN 3 MINUTES
Inga [223]

Answer:

<u>1728 in²</u>

Step-by-step explanation:

For the area of B, you need to find the length and width (height and base, whatever you want to call it).

For the height, you would need to do: 144 - 36 - 24 - 36 = <u>48 inches</u>

For the base, you would need to do: 60 - 24 = <u>36 inches</u>

Now you multiply the base and height to get the area: 48 x 36 = <u>1728 in²</u>

7 0
2 years ago
What is the image of (-6,-5) after a reflection over the -axis
AfilCa [17]

If the axis is x then you go to y so (6, 5)

7 0
2 years ago
The side length of a square ice cube is claimed to be 1.0 inches, correct to within 0.001 inch. Use linear approximation to esti
Olenka [21]

Answer:

0.012

Step-by-step explanation:

Linear approximation says that,

f(x) \approx f(x_o)+f'(x_o)(x-x_o)

For a cube the surface area is 6x^2.

So the side is 1.0 inch in, the surface area is =6\times1^2 = 6 square inches.  

In Linear approximation means you ignore the term x_o^2 , if x_o is a small number, because then x_o^2 will be a very smalle number and that does not contribute much to the error.  

So the surface area is approximately,

6x^2=6x_o^2+12x_o(x-x_o)

So here, x=1.001, x_o=0.001

The error in the area is approximately,

12 \times 0.001=0.012

So the error is 0.012.


3 0
3 years ago
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