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antiseptic1488 [7]
3 years ago
12

Juan is reading a 312-page book for school. He reads 12 pages each day. How long will it take him to finish the the the book.it

is either ABC or D.A. 21 days.B. 26 days.C.31 days.D.51 days.
Mathematics
2 answers:
wolverine [178]3 years ago
7 0

Answer:

26 days

Step-by-step explanation:

so ur gonna need to diving 312 by 12 and than twelve goes into thirty one twice and the answer is 7 after u finish subtracting than u bring down the 2 and 72 goes into 12 about 6 times which is 72 also u get zero and the answer is 26

nikdorinn [45]3 years ago
4 0
B. 26 days because 312 days divided by 12 pages equals 26 days
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3 years ago
Use the arc length formula and the given information to find r. s = 12 cm, 0 = 360; r = ?
hjlf
use s=r0

but first convert 360 degree to radian
you will get 6.284 radian

then you substitute and get the answer!

12= r (6.284)
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3 years ago
Given the circle with the equation (x + 1)2 + y2 = 36, determine the location of each point with respect to the graph of the cir
kati45 [8]
\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad 
radius=\stackrel{}{ r}\\\\
-------------------------------\\\\
(x+1)^2+y^2=36\implies [x-(\stackrel{h}{-1})]^2+[y-\stackrel{k}{0}]^2=\stackrel{r}{6^2}~~~~
\begin{cases}
\stackrel{center}{(-1,0)}\\
\stackrel{radius}{6}
\end{cases}

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\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
A(\stackrel{x_2}{-1}~,~\stackrel{y_2}{1})\qquad \qquad 
%  distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
\stackrel{distance}{d}=\sqrt{[-1-(-1)]^2+(1-0)^2}\implies d=\sqrt{(-1+1)^2+1^2}
\\\\\\
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\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
B(\stackrel{x_2}{-1}~,~\stackrel{y_2}{6})\\\\\\
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\\\\\\
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notice, the distance to B is exactly 6, and you know what that means.

\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
C(\stackrel{x_2}{4}~,~\stackrel{y_2}{-8})
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\stackrel{distance}{d}=\sqrt{[4-(-1)]^2+[-8-0]^2}\implies d=\sqrt{(4+1)^2+(-8)^2}
\\\\\\
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notice, C is farther than the radius 6, meaning is outside the circle, hiking about on the plane.
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3 years ago
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