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vodka [1.7K]
3 years ago
13

Find the product (7v+8)(4v2 - 8v+1)

Mathematics
2 answers:
Misha Larkins [42]3 years ago
5 0

7v(4v2-8v+1)+8(4v2-8v+1)

28v3-56v2+7v+32v2-64v+8

Answer= 28v3 -24v2 -57v +8

Bess [88]3 years ago
4 0
The answer is shown in the pic and the works to show how to get the answer

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3 years ago
Question 6<br> - Which is the graph of y=3/4x-3
algol [13]

Answer:

tthe middle graph.

Step-by-step explanation:

rise over run which is 3/4. so you start at (0,0) and go up 3 and over 4 and then down 3

4 0
3 years ago
Wich steps are needed to solve this equation b+6=21
blondinia [14]

Answer:

A

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
If the relationship is proportional, what is the missing value from the table
lesya [120]

Given:

Consider the below figure attached with this question.

The table represents a proportional relationship.

To find:

The missing value from the table.

Solution:

If y is proportional to x, then

y\propto x

y=kx                 ...(i)

Where, k is a constant of proportionality.

The relationship passes through the point (-3,-1). Substituting x=-3,y=-1 in (i), we get

-1=k(-3)

\dfrac{-1}{-3}=k

\dfrac{1}{3}=k

Putting k=\dfrac{1}{3} in (i), we get

y=\dfrac{1}{3}x           ...(ii)

We need to find the y-value for x=-12.

Substituting x=-12 in (ii), we get

y=\dfrac{1}{3}(-12)

y=-4

Therefore, the missing value in the table is -4. Hence, option D is correct.

7 0
3 years ago
The endpoints of EF are E(2, 3) and F(8, 11). The midpoint of EF is M.<br> Find the length of EM.
Serga [27]

The midpoint of EF is M. The length of EM is 5

Given :

The endpoints of EF are E(2, 3) and F(8, 11).

M is the midpoint of EF

Lets find out the midpoint M using midpoint formula

(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )\\E (x_1,y_1) is (2,3)\\F(x_2,y_2) is (8,11)

Substitute the values inside the formula

(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )\\\\(\frac{2+8}{2} ,\frac{3+11}{2} )\\\\(5,7)

Midpoint M is (4,7)

Now to find out length of EM, we use distance formula

Distance = \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}\\\mathrm{The\:distance\:between\:}\left(2,\:3\right)\mathrm{\:and\:}\left(5,\:7\right)\\\sqrt{\left(5-2\right)^2+\left(7-3\right)^2}\\\sqrt{3^2+4^2} \\\sqrt{25}\\5

So, length of EM= 5

Learn more :  brainly.com/question/18332427

5 0
3 years ago
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