Take the deritivive
remember
the deritivive of f(x)/g(x)=(f'(x)g(x)-g'(x)f(x))/(g(x)^2)
so
deritiveive is ln(x)/x is
remember that derivitive of lnx is 1/x
so
(1/x*x-1lnx)/(x^2)=(1-ln(x))/(x^2)
the max occurs where the value is 0
(1-ln(x))/(x^2)=0
times x^2 both sides
1-lnx=0
add lnx both sides
1=lnx
e^1=x
e=x
see if dats a max or min
at e/2, the slope is positive
at 3e/2, the slope is negative
changes from positive to negative at x=e
that means it's a max
max at x=e
I realize I didn't find the max point, so
sub back
ln(x)/x
ln(e)/e
1/e
the value of the max would be 1/e occuring where x=e
4th option is answer (1/e) because that is the value of the maximum (which happens at x=e)
Multiply every coordinate by the scale factor 3
(-1,2,0) ----> (-3,6,0) is the answer
The answer is 5/7 . 30/2=15 42/2=21 15/3=5 21/3=7
Answer:
57pi
Step-by-step explanation:
First, let's get the area of the entire circle, including the shaded region:
pi*(8+3)^2 = 121pi
Next, let's get the area of the unshaded circle
pi*8^2 = 64pi
If we subtract the inner circle from the full circle, we get the shaded region:
121pi-64pi =
57pi
4.20/7 = $0.6 That's for ONE candy
Then do this : 0.6* 12 = $7.20