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MatroZZZ [7]
3 years ago
7

I have no idea what to do with this someone help

Mathematics
2 answers:
joja [24]3 years ago
4 0
The given distance of 5.20 would be A.

Replace A with 5.20 to solve for T.

T = 5.20^3/2
T = 11.9 years.
Naddik [55]3 years ago
3 0
I think the answer is 11.8 years. Hope this helps.
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Write each fraction as a percent 4/100
nadezda [96]

Answer:

4%is the answer you are looking for

8 0
3 years ago
Read 2 more answers
Mrs Katie constructs a cube with 512 magnetic block students and her two classes will each make an identical cube. There are 28
devlian [24]
I take it each student is going to make a block. 
She has 25 + 28 students all together which is 53 students total
Each one requires 512 magnetic blocks

Therefore she needs 53 * 512 = 27136 blocks. 

6 0
3 years ago
Which equation has the solution x=-4? a 2(x-4)=16 b 3x+6-2x=-2 c 1/4x+4=3 d(x+6)3=-6 need help plz
xz_007 [3.2K]

Answer:

C: 1/4x + 4 = 3

Step-by-step explanation:

1/4x + 4 = 3

1/4x = 3 - 4

x = - 4

Thus, option c gives out the solution x = - 4.

4 0
3 years ago
OKAY i CANT EVEN FIGURE THIS ONE OUT NEED HELP.<br> -3 (5 – 2y)
inessss [21]

negative multiplied by positives = negative numbers

3 x 5 = -15

negative multiplied by a negative = a positive number

-3 x -2y = +6y

so combine both gets -15 +6y

or a better way to write it is 6y-15

5 0
3 years ago
Use the intermediate value theorem to find the value of c such that f(c) = M. f(x) = x^2 - x + 1 text( on ) [1,8]; M = 21 c =
DanielleElmas [232]

Answer:

c = 5

Step-by-step explanation:

Given

f(c) = M

f(x) = x^2 - x + 1

Interval: [1,8]

M = 21

Required

Find c using Intermediate Value theorem

First, check if the value of M is within the given range:

f(x) = x^2 - x + 1

f(1) = 1^2 - 1 + 1

f(1) = 1

f(x) = 8^2 - 8 + 1

f(x) = 57

1 \le M \le 57

1 \le 21 \le 57

M is within range.

Solving further:

We have:

f(c) = f(x) = M

f(x) = 21

Substitute 21 for f(x) in f(x) = x^2 - x + 1

21 = x^2 - x + 1

Express as quadratic function

x^2 - x + 1 - 21  = 0

x^2 - x - 20  = 0

Expand

x^2 + 4x - 5x - 20

x(x+4)-5(x+4)=0

(x - 5)(x+4) = 0

x - 5 = 0 or x + 4= 0

x = 5 or x = -4

The value of x = -4 is outside the Interval: [1,8]

So:

x = 5

f(c) = f(x) = M

f(c) = f(5) = 21

By comparison:

c = 5

4 0
3 years ago
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