both resistance will have same voltage across it which is equal to 5 volt.
if resistance value is different then voltage drop across them will be different.
current in both resistance would be same.
let's say resistance is 5 ohm of each one.
total current = total voltage / total resistance
= 10 /(5+5) = 10/10 = 1 amp
now voltage across 5 Ohm resistance = current × resistance = 1× 5 = 5 volt
Answer:
not 100% but i think its 1.57x10^20
Explanation:
5.25x10^-4g / 2.016g
2.60x10^-4 x 6.022x10^23= 1.56x10^20 molecules
39.25 g of water (H₂O)
Explanation:
We have the following chemical reaction:
2 H₂ + O₂ → 2 H₂O
Now we calculate the number of moles of each reactant:
number of moles = mass / molar weight
number of moles of H₂ = 14.8 / 2 = 7.4 moles
number of moles of O₂ = 34.8 / 32 = 1.09 moles
We see from the chemical reaction that 2 moles of H₂ will react with 1 mole of O₂ so 7.4 moles of H₂ will react with 3.7 moles of O₂ but we only have 1.09 moles of O₂ available. The O₂ will be the limiting reactant. Knowing this we devise the following reasoning:
if 1 moles of O₂ produces 2 moles of H₂O
then 1.09 moles of O₂ produces X moles of H₂O
X = (1.09 × 2) / 1 = 2.18 moles of H₂O
mass = number of moles × molar weight
mass of H₂O = 2.18 × 18 = 39.25 g
Learn more about:
limiting reactant
brainly.com/question/7144022
brainly.com/question/6820284
#learnwithBrainly
Answer:
Explanation:
Calcium carbonate decomposes at high temperatures to give calcium oxide and carbon
dioxide as shown below.
CaCO3(s) = CaO(s) + CO2(g)
The Kp for this reaction is 1.16 at 800°C. A 5.00 L vessel containing 10.0 g of CaCO3(s)
was evacuated to remove the air, sealed, and then heated to 800°C. Ignoring the volume
occupied by the solid, what will overall mass percent of carbon in the solid once equilibrium is reached?
