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Assoli18 [71]
3 years ago
7

Write the combustion equation for propane (C3H8). What is the sum of the coefficients for the reactants and products? Group of a

nswer choices 13 14 10 11 12
Chemistry
1 answer:
lbvjy [14]3 years ago
8 0

Answer:

13

Explanation:

Let's consider the unbalanced equation for the combustion of propane.

C₃H₈ + O₂ ⇒ CO₂ + H₂O

We will begin balancing H atoms by multiplying H₂O by 4.

C₃H₈ + O₂ ⇒ CO₂ + 4 H₂O

Now, we balance C atoms by multiplying CO₂ by 3.

C₃H₈ + O₂ ⇒ 3 CO₂ + 4 H₂O

Finally, we get the balanced equation multiplying O₂ by 5.

C₃H₈ + 5 O₂ ⇒ 3 CO₂ + 4 H₂O

The sum of the coefficients is 1 + 5 + 3 + 4 = 13.

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Answer:

Yes you are right.

Explanation:

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Give the oxidation state of the metal species in each complex. ru(cn)(co)4 -
kogti [31]
The given complex ion is as follow,

                                              [Ru (CN) (CO)₄]⁻

Where;
            [ ]  =  Coordination Sphere

            Ru  =  Central Metal Atom  =  <span>Ruthenium

            CN  =  Cyanide Ligand

            CO  =  Carbonyl Ligand

The charge on Ru is calculated as follow,

                               Ru + (CN) + (CO)</span>₄  =  -1
Where;
            -1  =  overall charge on sphere

             0  =  Charge on neutral CO

            -1  =  Charge on CN

So, Putting values,


                               Ru + (-1) + (0)₄  =  -1

                               Ru - 1 + 0  =  -1

                               Ru - 1  =  -1

                               Ru  =  -1 + 1

                               Ru  =  0
Result:
          <span>Oxidation state of the metal species in each complex [Ru(CN)(CO)</span>₄]⁻ is zero.
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