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3 years ago

Three sides of a triangle measure 10m, 12m, and 18m. Find the largest angle of the triangle to the nearest degree.

Mathematics

1 answer:

sweet-ann [11.9K]3 years ago

8 0

Answer:

109°

Step-by-step explanation:

The Law of Cosines is good for finding angles when you know three sides. It tells you ...

a^2 = b^2 + c^2 -2bc·cos(A)

where a, b, c are the side lengths and A, B, C are the opposite angles. Here, we want a=18, since the longest side is opposite the largest angle.

Solving for cos(A), we get ...

(b^2 +c^2 -a^2)/(2bc) = cos(A)

A = arccos((b^2 +c^2 -a^2)/(2bc)) = arccos((10^2 +12^2 -18^2)/(2·10·12))

= arccos(-80/240) = arccos(-1/3) ≈ 109.471°

The largest angle of the triangle is about 109°.

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3 years ago

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jasenka [17]

Answer:

x=30, and angle A equals 132°.

Step-by-step explanation:

Since the angles are alternate-interior, both angles A and B equal the same amount. To figure out the value of x, you'd need to set up your equation like this:

5x-18°=3x+42°

You would need to solve for x, which should equal to 30.

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3 years ago

A regular 12-oz beer is about 5% alcohol. This works out to about 14.03 grams of alcohol per beer. If the driver drank two beers

solong [7]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago

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For this case you must simplify the expression respecting the rules of multiplication of mathematics.
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